2. Business Programming I Fall – 2000 By Jim Payne

3. Lecture 05Jim Payne - University of Tulsa2 Alphanumeric Storage Numbers that are not numbers? Alphabetic Characters A,B,C,a,b,c Special Symbols * ( [ { ? / + :

4. Lecture 05Jim Payne - University of Tulsa3 Coding Systems EBCDIC EBCDIC – used in many mainframes Extended Binary Coded Decimal Interchange Code An IBM coding system used mainly on mainframe computers ASCII ASCII – used on most PC’s American Standard Code for Information Interchange

5. Lecture 05Jim Payne - University of Tulsa4

6. Lecture 05Jim Payne - University of Tulsa5 2 3 2 2 1 2 0 8421 00010100 The capital letter A has a hex value of 41, and a binary value of

7. Lecture 05Jim Payne - University of Tulsa6 2 3 2 2 1 2 0 8421 01110011 The alphanumeric 7 has a hex code of 37, and a coded binary ascii code of

8. Lecture 05Jim Payne - University of Tulsa7 2 3 2 2 1 2 0 8421 What is the binary equivalent of GO TU!

9. Lecture 05Jim Payne - University of Tulsa8 HD 1.4MB diskette 2 sides * 80 tracks * 18 sectors = 2880 allocation units @ 512 bytes each Total space = 1,474,560 bytes Less 33 allocation units for system information = Available Storage = 1,457,664 bytes

10. Lecture 05Jim Payne - University of Tulsa9 Tracks 80 Sector 18 Allocation unit 2880 @ 512 bytes each Sides 2

11. Lecture 05Jim Payne - University of Tulsa10 1 allocation unit 512 bytes = 4096 bits 0100000101000001……. magnetized spots

12. Lecture 05Jim Payne - University of Tulsa11 Convert to Binary? The number 11 The alphanumeric 11 The zip code 74104 The salary 74104

13. Lecture 05Jim Payne - University of Tulsa12 CPU Input Output Primary RAM 10101010 10101001 00101000 10101010 10010101 01010101 switches How many bytes? How many bits? in each

14. Lecture 05Jim Payne - University of Tulsa13 CPU Input Output 64MB of RAM 1024*1024 = 1,048,576 = 1 Megabyte * 64 = 67,108,864 bytes * 8 = 536,870,910 bits or switches Disks: 1.4MB 10 Gigabytes 100 MB Zip

15. Lecture 05Jim Payne - University of Tulsa14