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Section 9.3 The Parabola. Finally, something familiar! The parabola is oft discussed in MTH 112, as it is the graph of a quadratic function: Does look.

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Presentation on theme: "Section 9.3 The Parabola. Finally, something familiar! The parabola is oft discussed in MTH 112, as it is the graph of a quadratic function: Does look."— Presentation transcript:

1 Section 9.3 The Parabola

2 Finally, something familiar! The parabola is oft discussed in MTH 112, as it is the graph of a quadratic function: Does look familiar? Our discussion of the parabola will be consistent with our discussion of the other conic sections.

3 The Parabola A parabola is the set of all points in the plane that are the same distance from a given point (focus) as they are from a given line (directrix). It is important to note that the focus is not a point on the directrix. While the directrix can be any line, we only consider horizontal and vertical ones.

4 Parabolic Parts The axis of symmetry of a parabola is an imaginary line perpendicular to the directrix that passes through the focus. The axis of symmetry intersects the parabola at a point called the vertex. Let p be the distance from the vertex to the focus. It follows that p is also the distance from the vertex to the directrix.

5 More Pictures

6 Equations The standard form of the equation of a parabola with horizontal directrix is When p is positive, the parabola opens upward. When p is negative, the parabola opens downward.

7 Equations (cont.) The standard form of the equation of a parabola with vertical directrix is When p is positive, the parabola opens to the right. When p is negative, the parabola opens to the left.

8 Giggle, giggle The latus rectum is a line segment that: 1.passes through the focus; 2.Is parallel to the directrix; 3.Has its endpoints on the parabola. The length of the latus rectum is 4p.

9 Pictures

10 Finally… Draw the picture. And, when all else fails…. Draw the picture.

11 Examples Find the vertex, focus and directrix, and sketch the graph. 1.x 2 = 24y 2.y 2 = 40x 3.(x + 2) 2 = -4(y – 1) Find the standard form of the equation the parabola so described: 1.Focus is (12, 0); directrix is x = -12 2.Vertex is (3, -1); focus is (3, -2)

12 More Examples Convert to standard form by completing the square on x: x 2 + 6x – 12y – 15 = 0 Convert to standard form by completing the square on y: y 2 – 12y + 16x + 36 = 0


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