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Published byLoren Bailey Modified over 9 years ago
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substances that include water into their formula water is not actually part of the chemical substance and this is reflected in the way the formula is written
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For every one CuSO 4, there are five water molecules The dot IS NOT a multiplication sign. Remember, this is chemistry, not math.
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No, the substance is not wet, it appears dry. There are some hydrates that have a wet appearance, but most appear perfectly dry to the eye and to the touch.
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penta meaning five and hydrate meaning water CuSO 4. 5 H 2 O
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Suppose you heard "trihydrate." What would you write?
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. 3 H 2 O
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Suppose you heard "octahydrate." What would you write?
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. 8 H 2 O
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Name this substance: MgSO 4. 9 H 2 O
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Magnesium sulfate nonahydrate
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Write the formula for: barium chloride dihydrate
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BaCl 2. 2 H 2 O
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Keep water’s mass separate in calculation CuSO 4. 5 H 2 O Cu = 63.5 g S = 32.1 g O = 16.0 x 4 = 64.0 g H 2 O = 18.0 g x 5 = 90.0g › Add them all together to get the molar mass Total = 249.6 g (MOLAR MASS)
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Calculating the accepted value: How much water did we have? › 90.0 grams H 2 O What was the total molar mass? › 249.6 grams 90.0 g x 100 = 36.1% H 2 O 249.6 g
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You begin an experiment with 15.0 grams of hydrate. You place the hydrate in an evaporating dish and place the Bunsen burner below. You weigh your resulting product, 13.2 grams of anhydrous salt (a compound with all the water removed). Determine the experimental percent composition of water within the compound
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15.0 grams – 13.2 grams = 1.8 grams of water that was evaporated (removed) 1.8 g x 100 = 12.0% H 2 O 15.0 g
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