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Published byOswin Spencer Modified over 9 years ago
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Graphing Parabolas Using the Vertex Axis of Symmetry & y-Intercept By: Jeffrey Bivin Lake Zurich High School jeff.bivin@lz95.org
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Graphing Parabolas y = x 2 + 4x - 7 With your graphing calculator, graph each of the following quadratic equations and identify the vertex and axis of symmetry. y = 2x 2 + 10x + 4 y = -3x 2 + 5x + 9
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Graph the following parabola y = x 2 + 4x - 7 axis of symmetry: vertex: y-intercept:
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Graph the following parabola y = 2x 2 + 10x + 4 axis of symmetry: vertex: y-intercept:
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Graph the following parabola y = -3x 2 + 5x + 9 axis of symmetry: vertex: y-intercept:
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Graphing Parabolas y = x 2 + 4x - 7 Now look at the coefficients of the equation and the value of the axis of symmetry – especially a and b y = ax 2 + bx + c y = 2x 2 + 10x + 4 y = -3x 2 + 5x + 9
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Graphing Parabolas y = ax 2 + bx + c Vertex: Axis of symmetry:
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Graph the following parabola y = x 2 + 4x - 7 axis of symmetry: vertex: y-intercept:
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Graph the following parabola y = 2x 2 + 10x + 4 axis of symmetry: vertex: y-intercept:
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Graph the following parabola y = -3x 2 + 5x + 9 axis of symmetry: vertex: y-intercept: Why did this parabola open downward instead of upward as did the previous two?
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Graph the following parabola y = x 2 + 6x - 8 Axis of symmetry: Vertex: y-intercept:
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Graph the following parabola y = -2x 2 + 7x + 12 Axis of symmetry: Vertex: y-intercept:
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Some Web Sites http://www.xahlee.org/SpecialPlaneCurves_dir/Parabola_dir/parabolaReflect.mov
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