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Analysis of SRPT Scheduling: Investigating Unfairness Nikhil Bansal (Joint work with Mor Harchol-Balter)

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Presentation on theme: "Analysis of SRPT Scheduling: Investigating Unfairness Nikhil Bansal (Joint work with Mor Harchol-Balter)"— Presentation transcript:

1 Analysis of SRPT Scheduling: Investigating Unfairness Nikhil Bansal (Joint work with Mor Harchol-Balter)

2 Aim: “Good” Scheduling Policy Low Response times Fair Motivation Problem Server Client1 Client2 Client3

3 Time Sharing (PS) Server shared equally between all the jobs:  Low response times  Fair  Does not require knowledge of sizes Can we do better ?

4 Shortest Remaining Proc. Time Optimal for minimizing mean response times.  Knowledge of sizes  Improvements significant ?  Starvation of large jobs Biggest fear Objections:

5 Questions  Smalls better Bigs worse  How do means compare  Elephant-mice property and implications

6 M/G/1 Queue Framework ArrivalsqueueServer Load( ) = (arrival rate).E[S] Poisson Arrival Process with rate Job sizes (S) iid general distribution F

7 Queueing Formulas for PS E[T(x)]: Expected Response time for job of size x [Kleinrock 71] Identical for all!

8 M/G/1 SRPT        x x SRPT t dt x xFx tft xTE 0 2 2 0 2 ))(1( (1(2 )))(1()(( )]([   Waiting Time (E[W(x)])Residence Time (E[R(x)])  Load up to x  Variance up to x  Gains priority after it begins execution 

9 All-Can-Win under srpt put c Thm: Every job prefers SRPT, when load <= ½, for all job size distributions. Proof: Know that If Key Observation Holds for all x, if load <= 0.5

10 What if load > 0.5 ? problem Still holds if Irrespective of The Heavy-Tailed Property: (Elephant -Mice) 1% of the big jobs make up at least 50% of the load. For a distribution with the HT property, >99% of jobs better under SRPT In fact, significantly better, Under SRPT, Bounded by 4 Arbitrarily high

11 The very largest jobs  If load <= 0.5, all jobs favor SRPT.  At any load, > 99% jobs favor SRPT, if HT property. Moreover significant improvements. What about the remaining 1% largest jobs?

12 1. Bounding the damage theorem 2. As Implication: Mean slowdown of largest 1% under SRPT: Same as PS Fill in…

13 Insert plots here: 1 for BP 1.1 with load 0.9 showing how all Do better 2 for exp with load 0.9 showing how some do bad.

14 Other Scheduling Policies  Non-preemptive: i.First Come First Serve (FCFS) ii.Random iii.Last Come First Serve (LCFS) iv.Shortest Job First (SJF)  Preemptive: i.Foreground Background (FB) ii.Preemptive LCFS Same as PS Trivially worse Very bad mean Performance, for HT workloads

15 Overload Add some lines for why good + we do work on this in paper

16 Actual Implementation Add a plot or couple of lines

17 Conclusions Significant mean performance improvements. Big jobs prefer SRPT under low-moderate loads. Big jobs prefer SRPT even under high loads for heavy-tailed distributions.

18 Scratch

19 Under h-t distributions Load = 0.9 Heavy-tailed distribution with alpha=1.1 Job PercentileSRPTPS 90%1.2810 99%1.6210 99.9%2.0810 99.99%2.6910 100%9.5410 Very largest job

20 Under light-tailed distributions Job PercentileSRPTPS 90%3.1710 95%4.9310 99%11.1410 99.9%16.0110 Load=0.9 Exponential distribution


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