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Dr. Bernard Chen Ph.D. University of Central Arkansas Spring 2010

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1 Dr. Bernard Chen Ph.D. University of Central Arkansas Spring 2010
Exam2 Review Dr. Bernard Chen Ph.D. University of Central Arkansas Spring 2010

2 Outline Pipeline Memory Hierarchy

3 Parallel processing A parallel processing system is able to perform concurrent data processing to achieve faster execution time The system may have two or more ALUs and be able to execute two or more instructions at the same time Goal is to increase the throughput – the amount of processing that can be accomplished during a given interval of time

4 Parallel processing classification
Single instruction stream, single data stream – SISD Single instruction stream, multiple data stream – SIMD Multiple instruction stream, single data stream – MISD Multiple instruction stream, multiple data stream – MIMD

5 9.2 Pipelining Instruction execution is divided into k segments or stages Instruction exits pipe stage k-1 and proceeds into pipe stage k All pipe stages take the same amount of time; called one processor cycle Length of the processor cycle is determined by the slowest pipe stage k segments

6 SPEEDUP If we execute the same task sequentially in a single processing unit, it takes (k * n) clock cycles. • The speedup gained by using the pipeline is:

7 Example A non-pipeline system takes 100ns to process a task;
the same task can be processed in a FIVE-segment pipeline into 20ns, each Speedup Ratio for 1000 tasks: 100*1000 / ( )*20 = 4.98 However, if the task cannot be evenly divided…

8 Example A non-pipeline system takes 100ns to process a task;
the same task can be processed in a six-segment pipeline with the time delay of each segment in the pipeline is as follows 20ns, 25ns, 30ns, 10ns, 15ns, and 30ns. Determine the speedup ratio of the pipeline for 10, 100, and 1000 tasks. What is the maximum speedup that can be achieved?

9 Example Answer Speedup Ratio for 10 tasks:
100*10 / (6+10-1)*30 Speedup Ratio for 100 tasks: 100*100 / ( )*30 Speedup Ratio for 1000 tasks: 100*1000 / ( )*30 Maximum Speedup: 100*N/ (6+N-1)*30 = 10/3

10 Instructions seperate
1. Fetch the instruction 2. Decode the instruction 3. Fetch the operands from memory 4. Execute the instruction 5. Store the results in the proper place

11 5-Stage Pipelining S1 S2 S3 S4 S5 Time 1 2 3 4 9 8 7 6 5 S1 S2 S5 S3
Fetch Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO) Time 1 2 3 4 9 8 7 6 5 S1 S2 S5 S3 S4

12 Pipeline Hazards There are situations, called hazards, that prevent the next instruction in the instruction stream from executing during its designated cycle There are three classes of hazards Structural hazard Data hazard Branch hazard

13 Data hazard Example: ADD R1R2+R3 SUB R4R1-R5 AND R6R1 AND R7
OR R8R1 OR R9 XOR R10R1 XOR R11

14 Data hazard FO: fetch data value WO: store the executed value S1 S2 S3
Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO) Time

15 Data hazard ADD R1R2+R3 No-op SUB R4R1-R5 AND R6R1 AND R7
Delay load approach inserts a no-operation instruction to avoid the data conflict ADD R1R2+R3 No-op SUB R4R1-R5 AND R6R1 AND R7 OR R8R1 OR R9 XOR R10R1 XOR R11

16 Data hazard

17 Data hazard It can be further solved by a simple hardware technique called forwarding (also called bypassing or short-circuiting) The insight in forwarding is that the result is not really needed by SUB until the ADD execute completely If the forwarding hardware detects that the previous ALU operation has written the register corresponding to a source for the current ALU operation, control logic selects the results in ALU instead of from memory

18 Data hazard

19 Branch hazards Branch hazards can cause a greater performance loss for pipelines When a branch instruction is executed, it may or may not change the PC If a branch changes the PC to its target address, it is a taken branch Otherwise, it is untaken

20 Branch hazards There are FOUR schemes to handle branch hazards
Freeze scheme Predict-untaken scheme Predict-taken scheme Delayed branch

21 Branch Untaken (Freeze approach)
The simplest method of dealing with branches is to redo the fetch following a branch Fetch Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO)

22 Branch Taken (Freeze approach)
The simplest method of dealing with branches is to redo the fetch following a branch Fetch Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO)

23 Branch Untaken (Predicted-untaken)
Fetch Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO) Time

24 Branch Taken (Predicted-untaken)
Fetch Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO)

25 Branch Untaken (Predicted-taken)
Fetch Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO)

26 Branch taken (Predicted-taken)
Fetch Instruction (FI) Decode Instruction (DI) Fetch Operand (FO) Execution Instruction (EI) Write Operand (WO)

27 Delayed Branch A fourth scheme in use in some processors is called delayed branch It is done in compiler time. It modifies the code The general format is: branch instruction Delay slot branch target if taken

28 Delayed Branch Optimal

29 Outline Pipeline Memory Hierarchy

30 Memory Hierarchy The main memory occupies a central position by being able to communicate directly with the CPU and with auxiliary memory devices through an I/O processor A special very-high-speed memory called cache is used to increase the speed of processing by making current programs and data available to the CPU at a rapid rate

31 RAM

32 ROM

33 Memory Address Map

34

35 Cache memory When the CPU refers to memory and finds the word in cache, it is said to produce a hit Otherwise, it is a miss The performance of cache memory is frequently measured in terms of a quantity called hit ratio Hit ratio = hit / (hit+miss)

36 Cache memory The basic characteristic of cache memory is its fast access time, Therefore, very little or no time must be wasted when searching the words in the cache The transformation of data from main memory to cache memory is referred to as a mapping process, there are three types of mapping: Associative mapping Direct mapping Set-associative mapping

37 Associative mapping

38 Direct Mapping

39 Direct Mapping

40 Set-Associative Mapping

41 Average memory access time
% instructions * (Hit_time + instruction miss rate*miss_penality) + % data * (Hit_time + data miss rate*miss_penality)

42 Average memory access time
Assume 40% of the instructions are data accessing instruction. Let a hit take 1 clock cycle and the miss penalty is 100 clock cycle Assume instruction miss rate is 4% and data access miss rate is 12%, what is the average memory access time? 60% * (1 + 4% * 100) + 40% * (1 + 12% * 100) = 0.6 * (5) * (13) = 8.2 (clock cycle)

43 Page Fault

44 Performance of Demand Paging
Page Fault Rate 0 ≤p≤1.0 if p= 0 no page faults if p= 1, every reference is a fault Effective Access Time (EAT)= (1-p)*ma + p*page fault time

45 9.4 Page Replacement What if there is no free frame?
Page replacement –find some page in memory, but not really in use, swap it out In this case, same page may be brought into memory several times

46 9.4 Page Replacement Many Approaches: FIFO
Optimal Page-Replacement Algorithm Least-recently-used (LRU) Second-Chance Algorithm Least Frequently used (LFU) page-replacement algorithm Most frequently used (MFU) page-replacement algorithm


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