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Published byCrystal Ray Modified over 9 years ago
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Kinetic Energy work of changing speed § 6.2
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Rebounding Ball What is the sign of the work done on the ball by the wall as it slows (squishes)? A.Positive (W > 0). B.Negative (W < 0). C.Zero (W = 0). D.Can’t tell (W = ?).
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Rebounding Ball What is the sign of the work done on the ball by the wall as it rebounds (expands)? A.Positive (W > 0). B.Negative (W < 0). C.Zero (W = 0). D.Can’t tell (W = ?).
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Happy/Sad Balls Which ball has the greatest change in kinetic energy K during impact? A.The happy (rebounding) ball. B.The sad (dead) ball. C.Both had the same K.
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Happy/Sad Balls Which ball has the most (largest absolute value) work done on it during impact? A.The happy (rebounding) ball. B.The sad (dead) ball. C.Both had the same W.
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Work in General changing forces, curving paths § 6.3
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What’s the point? What is work when force is not constant or the path is not straight?
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Work in General For constant force, W = F·s. In general, dW = F·ds. So, W = F·ds. (Sum of work done over each interval.) Path may not be straight. F may vary with position or time.
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Elastic Force Stretching and squishing still § 6.3
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Hooke’s Law Formula F = force exerted by the spring k = spring constant; units: N/m; k > 0 x = displacement from equilibrium position negative sign: force opposes distortion F = –kx
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Work to Deform a Spring Push or pull a distance x from equilibrium x kx force displacement kx 2 1 2 = slope = k area = w Work =F·x ; 1 2 F = kx Work = kx·x 1 2
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Poll Question A spring with force constant k is stretched from x = 0 to x = D. What is the work done by the spring as it stretches? A.1/2 kD 2. B.–1/2 kD 2. C.0. D.It cannot be determined. E.None of these.
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Poll Question Two springs, one with a spring constant k 1 and the other with a spring constant k 2 = 2 k 1, are slowly stretched to the same final tension. Which spring has more work done on it? A.The stiffer spring (k = k 2 = 2 k 1 ) B.The softer spring (k = k 1 ) C.The same work was done on both.
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Centripetal Force work of acceleration § 6.3
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Group Poll Question A toy of mass m moving at constant speed v in a circle of radius r has a constant magnitude of centripetal acceleration of v 2 /r. Its velocity reverses every half-cycle. How much work does the centripetal force do on the toy every half-cycle? A. mv 2. B. –mv 2. C. mv 2. D. None of these.
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Kinetic Energy and Direction K depends on speed Direction of velocity is irrelevant Changing only direction requires force, but no work. 1/2 mv 2 = 1/2 mv v is a scalar.
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Net Force and Net Work Net force is nonzero if a body accelerates net work is nonzero if a body changes speed The net force must overlap with the displacement to do work!
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