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Physics 3.2 “Vector Operations” SOHCAHTOA. I. Determining Resultant Magnitude and Direction.

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Presentation on theme: "Physics 3.2 “Vector Operations” SOHCAHTOA. I. Determining Resultant Magnitude and Direction."— Presentation transcript:

1 Physics 3.2 “Vector Operations” SOHCAHTOA

2 I. Determining Resultant Magnitude and Direction

3 Assignment Practice 3A #’s 1-4 Answers: 1. a. 23 km b. 17 km to the east 2. 45.6 m at 9.5 deg east of north 3. 15.7 m at 22 deg to the side of downfield 4. 1.8 m at 49 deg below the horizon

4 II. Resolving Vectors into Components 35° 1200 km/hr 980 km/hr 690 km/hr

5 Assignment Practice 3B #’s 1, 2, 3, and 5 Answers: 1.95 km/hr 2.44 km/hr 3.21 m/s, 5.7 m/s 5. 1.1 x 10 2 m, -53 m

6 III. Adding Vectors that are not Perpendicular A.Not a right triangle… 1. Make one by: a. Finding vertical or horizontal components of displacement vectors. 2. Ex: A plane takes off with a speed of 125 km/hr. It then increases its speed to 255 km/hr at an angle of 45 deg. The plane then decreases its angle to 25 deg at a speed of 475 km/hr. What is the resultant? 830 km/hr and 27 N of E

7 Assignment pg. 97 Practice 3C #’s 1, 3 and 4 Answers: 1.49 m at 7.3 deg right of down field 3.13.0 m at 33 deg East of North 4.172 km at 34 deg East of North

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