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(For help, go to Lessons 1-2, 1-4 and 1-6.) Evaluate each formula for the values given. 1.distance: d = rt, when r = 60 mi/h and t = 3 h 2.perimeter of a rectangle: P = 2 + 2w, when = 11 cm, and w = 5 cm 3.area of a triangle: A = bh, when b = 8 m and h = 7 m 1212 Formulas ALGEBRA 1 LESSON 2-6 2-6
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Solutions 1.d = rt = 60(3) = 180 mi 2.P = 2 + 2w = 2(11) + 2(5) = 22 + 10 = 32 cm 3.A = bh = (8)(7) = 4(7) = 28 m 2 1212 1212 Formulas ALGEBRA 1 LESSON 2-6 2-6
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Solve the formula for the volume of a rectangular prism V = wh for width w in terms of its volume V, length, and its height h. V= wh =wh Simplify. V Formulas ALGEBRA 1 LESSON 2-6 2-6 = Divide each side by, = 0. V wh / = Divide each side by h, h = 0, to get w alone on one side of the equation. V h wh h / =w Simplify. V h
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Solve y = 4x – 3 for x. y + 3=4x – 3 + 3Add 3 to each side. y + 3=4xSimplify. Formulas ALGEBRA 1 LESSON 2-6 2-6 =Divide each side by 4. y + 3 4 4x44x4 =xSimplify. y + 3 4
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Solve z – br = p for b in terms of z, r, and p. z – br – z=p – zSubtract z from each side. –br=p – zCombine like terms. Formulas ALGEBRA 1 LESSON 2-6 2-6 =Divide each side by –r. –br –r p – z –r b=–Simplify. p – z –r
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The formula K = C + 273.15 gives the Kelvin temperature K in terms of the Celsius temperature C. Transform the formula to find Celsius temperature in terms of Kelvin temperature. Then, find the Celsius temperature when the Kelvin temperature is 400°. Solve for C. K=C + 273.15 K – 273.15=C + 273.15 – 273.15Subtract 273.15 from each side. K – 273.15=C Simplify. Find C when K = 400. 400 – 273.15=C Substitute 400 for K. 126.85=C 400º K is 126.85º C. Formulas ALGEBRA 1 LESSON 2-6 2-6
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Solve each equation for the given variable. 1. 3x + 2y = z; y2. = ; a 3. 3x + 4 = 2(3 – y); y 4.The formula v 2 = can be used to find the constant speed v of a satellite revolving around Earth in a circular orbit of radius r. G is a number known as the gravitational constant and M is the mass of Earth. Transform this formula to find the mass of Earth. a – b c d3d3 GM r M = v2rGv2rG Formulas ALGEBRA 1 LESSON 2-6 2-6 a = + b cd 3 y = z – x 1212 3232 y = – x + 1 3232
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