Download presentation
Presentation is loading. Please wait.
Published byMarilyn Wiggins Modified over 9 years ago
1
The parabola Presenter Name : Kamalasai School, Kalasin Province Mr.Pramote Phothisai (a,0) (-a,0) v
2
Objective 1.Determine the equation of the parabola when given a vertex and a focus. 2. Determine the coordinates of the vertex and the focus of the parabola described by the equation.
3
Interesting Words Entirely Parabola Focus Vertex Curve Upward Downward Equidistant Directrix Length
4
Phrases referring to what we will talk about A parabola is the locus of all points In a plane equidistant from a fixed point Between the focus and the directrix Is called the vertex of the parabola The curve lies entirely The curve opens upward The curve opens downward
5
The parabola A parabola is the locus of all points in a plane Point V which lies halfway between the focus and the directrix, is called the vertex of the parabola. v (a,0) (-a,0) directrix X Y equidistant from a fixed point, called the focus, and a fixed line, called the directrix.
6
The distance from the point (x,y) on the curve to the focus (a,0). (a,0)(-a,0) v X Y (x,y) directrix The distance from the point (x,y) on the directrix x = -a. Since by definition these two distance are equal, we may set them equal : We have an equation for the parabola: The curve must be entirely to the right of the Y-axis.
7
(a,0)(-a,0) v X Y For example F(2,0) F(3,0) Directrix x = -2 Directrix x = -3 Directrix V (0,0)
8
If the equation is : The curve lies entirely to the left of the Y-axis. (-a,0)(a,0) v For example F(-2,0) F(-3,0) Directrix x = 2 Directrix x = 3 Directrix V (0,0)
9
Find the equation of a parabola given the coordinates of its focus and vertex. Standard form Example 1 1) Focus (5, 0) and vertex at origin 2) Focus (-4, 0) and vertex at origin Solution1) Step 1 Step 2 5 Step 3 2) Step 1 Standard form Step 2 4( )x -4 Step 3
10
If the form of equation is : The curve opens upward and the focus is a point on the Y-axis. v (0,a) (0,-a) For example V (0,0) F(0,2) F(0,3) Directrix y = -2 Directrix y = -3 Directrix
11
If the form of equation is : The curve opens downward and the focus is a point on the Y-axis. v (0,a) (0,-a) V (0,0) For example F(0,-2) F(0,-3) Directrix y = 2 Directrix y = 3 Directrix
12
Find the equation of a parabola given the coordinates of its focus and vertex. Standard form Example 2 1) Focus (0, 7) and vertex at origin 2) Focus (0, -5) and vertex at origin Solution1) Step 1 Step 2 7 Step 3 2) Step 1 Standard form Step 2 4( )y -5 Step 3 4( )y
13
Kamalasai School, Kalasin Province up to now, all of the parabolas we have dealt with have had a vertex at the origin and a corresponding equation in one of the four following forms : 1) 2) 3) 4)
14
We will now present four more forms of the equation of a parabola. Each one is a standardize parabola with its vertex at point V(h, k). When the vertex is move from the When the vertex is move from the origin to the point V(h, k), the x and y terms of the equation are replaced by (x-h) and (y-k). Then the standard equation for the parabola that opens to the right is :
15
Example 3Reduce the equation Solution Rearrange the equation so that the second-degree term and any first-degree terms of the same unknown are on the left side. Then group the unknown term appearing only in the first- degree and all constants on the right : Then complete the square in y:
16
To get the equation in the form Factor an 8 out of the right side. Is the equation of the parabola with its vertex at (-1,3)
17
Example 4 Solution Reduce the equation Is the equation of the parabola with its vertex at (-1,-4)
18
OK. That’s it for today. See you next time. Thank you for your attention
Similar presentations
© 2025 SlidePlayer.com. Inc.
All rights reserved.