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Published byRoger Norris Modified over 9 years ago
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Find the angle of elevation of the sun when a 6-meter flagpole casts a 17-meter shadow.
After flying at an altitude of 575 meters, a helicopter starts to descend when its ground distance from the landing pad is 13.5 kilometers. What is the angle of depression for this part of the flight? The top of a signal tower is 250 feet above sea level. The angle of depression from the top of the tower to a passing ship is 19°. How far is the foot of the tower from the ship? Lesson 6 Menu
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Use the Law of Sines to solve triangles.
Solve problems by using the Law of Sines. Law of Sines solving a triangle Lesson 6 MI/Vocab
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Lesson 6 KC1
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A. Find p. Round to the nearest tenth.
Use the Law of Sines A. Find p. Round to the nearest tenth. Lesson 6 Ex1
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Use the Law of Sines Law of Sines Cross products
Divide each side by sin Use a calculator. Answer: p ≈ 4.8 Lesson 6 Ex1
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Use the Law of Sines B. Find mL to the nearest degree in ΔLMN if n = 7, ℓ = 9, and mN = 43. Law of Sines Cross products Divide each side by 7. Lesson 6 Ex1
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Use the Law of Sines Solve for L. Use a calculator. Answer: mL ≈ 61
Lesson 6 Ex1
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A. Find c to the nearest tenth.
B. 29.9 C. 7.8 D. 8.5 A B C D Lesson 6 CYP1
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B. Find mT to the nearest degree in ΔRST if r = 12, t = 7, and mR = 76.
C. 70 D. 44 A B C D Lesson 6 CYP1
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Solve Triangles A. Solve ΔDEF if mD = 8, mF = 112, and f = 12. Round angle measures to the nearest degree and side measures to the nearest tenth. We know the measures of two angles of the triangle. Use the Angle Sum Theorem to find Lesson 6 Ex2
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Subtract 120 from each side.
Solve Triangles Angle Sum Theorem Add. Subtract 120 from each side. Since we know and f, use proportions involving Lesson 6 Ex2
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d sin 112° = 12 sin 8° Cross products
Solve Triangles To find d: Law of Sines Substitute. d sin 112° = 12 sin 8° Cross products Divide each side by sin 112°. d ≈ 1.8 Use a calculator. Lesson 6 Ex2
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e sin 112° = 12 sin 60° Cross products
Solve Triangles To find e: Law of Sines Substitute. e sin 112° = 12 sin 60° Cross products Divide each side by sin 112°. Use a calculator. Answer: mE = 60; d ≈ 1.8; e ≈ 11.2 Lesson 6 Ex2
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30 sin 32° = 16 sin H Cross products
Solve Triangles B. Solve ΔHJK if mJ = 32, h = 30, and j = 16. Round angle measures to the nearest degree and side measures to the nearest tenth. 30 sin 32° = 16 sin H Cross products Lesson 6 Ex2
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mH + mJ + mK = 180 Angle Sum Theorem
Solve Triangles 83.5° = H Use a calculator. 84 ≈ mH mH + mJ + mK = 180 Angle Sum Theorem mK = 180 Substitute. 116 + mK = 180 Add. mK ≈ 64 Subtract 116 from each side. Lesson 6 Ex2
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k sin 32° = 16 sin 64° Cross products
Solve Triangles Law of Sines mJ = 32, mK = 64, j = 16 k sin 32° = 16 sin 64° Cross products Divide each side by sin k ≈ 27.3 Use a calculator. Answer: mH ≈ 84; mK ≈ 64; k ≈ 27.3 Lesson 6 Ex2
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A. For ΔRST, mR = 43, mT = 103, and r = 14. Find mS
A. For ΔRST, mR = 43, mT = 103, and r = 14. Find mS. Round measures to the nearest degree and side measures to the nearest tenth. A. 60 B. 68 C. 34 D. 146 A B C D Lesson 6 CYP2
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B. For ΔRST, mR = 43, mT = 103, and r = 14. Find s
B. For ΔRST, mR = 43, mT = 103, and r = 14. Find s. Round measures to the nearest degree and side measures to the nearest tenth. A. 17.1 B. 9.8 C. 11.5 D. 20.0 A B C D Lesson 6 CYP2
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C. For ΔRST, mR = 43, mT = 103, and r = 14. Find t
C. For ΔRST, mR = 43, mT = 103, and r = 14. Find t. Round measures to the nearest degree and side measures to the nearest tenth. A. 17.1 B. 9.8 C. 11.5 D. 20.0 A B C D Lesson 6 CYP2
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D. For ΔTUV, mT = 43, t = 12, and v = 9. Find mV
D. For ΔTUV, mT = 43, t = 12, and v = 9. Find mV. Round measures to the nearest degree and side measures to the nearest tenth. A. 49 B. 31 C. 65 D. 6 A B C D Lesson 6 CYP2
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E. For ΔTUV, mT = 43, t = 12, and v = 9. Find mU
E. For ΔTUV, mT = 43, t = 12, and v = 9. Find mU. Round measures to the nearest degree and side measures to the nearest tenth. A. 88 B. 72 C. 131 D. 106 A B C D Lesson 6 CYP2
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F. For ΔTUV, mT = 43, t = 12, and v = 9. Find u
F. For ΔTUV, mT = 43, t = 12, and v = 9. Find u. Round measures to the nearest degree and side measures to the nearest tenth. A. 16.9 B. 13.2 C. 16.7 D. 17.6 A B C D Lesson 6 CYP2
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Draw a diagram Draw Then find the
Indirect Measurement A 46-foot telephone pole tilted at an angle of 7° from the vertical casts a shadow on the ground. Find the length of the shadow to the nearest foot when the angle of elevation to the sun is 33°. Draw a diagram Draw Then find the Lesson 6 Ex3
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Indirect Measurement Since you know the measures of two angles of the triangle, and the length of a side opposite one of the angles you can use the Law of Sines to find the length of the shadow. Lesson 6 Ex3
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Answer: The length of the shadow is to about 75.9 feet.
Indirect Measurement Law of Sines Cross products Divide each side by sin Use a calculator. Answer: The length of the shadow is to about 75.9 feet. Lesson 6 Ex3
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A fishing pole is anchored to the edge of a dock
A fishing pole is anchored to the edge of a dock. If the distance from the foot of the pole to the point where the fishing line meets the water is 45 feet, about how much fishing line that is cast out is above the surface of the water? A. about 48 feet B. about 42 feet C. about 39 feet D. about 36 feet A B C D Lesson 6 CYP3
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Lesson 6 KC2
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