1. Dharamsinh Rathod Welcomes You http://dharam939.blogspot.in http://dharam939.blogspot.in

2. a[(sD an[ b[ez a[(sD-b[ez tTAY)krN bfr a[(sD-b[ez an&mipn http://dharam939.blogspot.in

3. tTAY)krNn) p\(k\yi jyir[ a[(sD an[ b[ezmi> a[ksrKi p\miNmi hieD^i[jn aiyn H + an[ hieD^i[ksieD aiyn OH - B[gi krvimi> aiv[ C[ Ryir[ mLt&> WivN tTAY hi[y C[. NaOH (aq) + HCl(aq) NaCl + H 2 O b[ez a[(sD xir piN) Ca(OH) 2 + 2 HCl CaCl 2 + 2H 2 O b[ez a[(sD xir piN) http://dharam939.blogspot.in

4. tTAY)krN  H 3 O + an[ OH -  H 3 O + an[ OH - aiyni[ B[gi Yen[ piN) bniv[ C[. H 3 O + + OH -  2 H 2 O H 3 O + + OH -  2 H 2 O a[(sD mi>Y) b[ez mi>Y) tTAY a[(sD mi>Y) b[ez mi>Y) tTAY a>(tm aiyn)k sm)krN: H + + OH -  H 2 O H + + OH -  H 2 O http://dharam939.blogspot.in

5. tTAY)krN miT[n& aiyn)k sm)krN aiyn Av$p[ p\bL a[(sD, b[ez an[ xir lKi[ H + + Cl - + Na + + OH - Na + + Cl - + H 2 O a[k srKi aiyni[n[ bid kri[. H + + Cl - + Na + + OH - Na + + Cl - + H 2 O a>(tm aiyn)k sm)krN H + + OH - H 2 O http://dharam939.blogspot.in

6. tTAY)krNni sm)krNn&> s>t&ln tTAY)krNni sm)krNn&> s>t&ln m[³n[S)ym hieD^i[ksieD an[ nieT^)k a[(sD vµc[ Yti tTAY)krN miT[n&> sm)krN lKi[. 1. a[(sD an[ b[ez ni s*#i[i lKi[. Mg(OH) 2 + HNO 3 OH - an[ H + aiynn) s>²yi a[ksrK) Yiy t[ r)t[ s>t&(lt kri[ 2. OH - an[ H + aiynn) s>²yi a[ksrK) Yiy t[ r)t[ s>t&(lt kri[ Mg(OH) 2 + 2 HNO 3 Mg(OH) 2 + 2 HNO 3 http://dharam939.blogspot.in

7. 3. upj lKi[ : Mg(OH) 2 + 2HNO 3 Mg(NO 3 ) 2 + H 2 O Mg(OH) 2 + 2HNO 3 Mg(NO 3 ) 2 + H 2 O xirpiN) (Fit& an[ aFit& ) (Fit& an[ aFit& ) 4. upjn[ s>t&(lt kri[ Mg(OH) 2 + 2 HNO 3 Mg(NO 3 ) 2 + 2 H 2 O Mg(OH) 2 + 2 HNO 3 Mg(NO 3 ) 2 + 2 H 2 O http://dharam939.blogspot.in

8. udihrN - 1 yi[³y g&Ni>k vD[ n)c[ aip[l tTAY)krNni sm)krNi[n[ s>t&(lt kri[. yi[³y g&Ni>k vD[ n)c[ aip[l tTAY)krNni sm)krNi[n[ s>t&(lt kri[. A. __ HCl + __ Al(OH) 3 __AlCl 3 + __ H 2 O 1) 1, 3, 3, 12) 3, 1, 1, 1 3) 3, 1, 1 3 B.__ Ba(OH) 2 + __H 3 PO 4 __Ba 3 (PO 4 ) 2 + __ H 2 O 1) 3, 2, 2, 22) 3, 3, 1, 6 3) 2, 3, 1, 6 http://dharam939.blogspot.in

9. uk[l - 1 A. 3HCl + 1Al(OH) 3 1AlCl 3 + 3H 2 O B. 3Ba(OH) 2 + 2H 3 PO 4 1Ba 3 (PO 4 ) 2 + 6H 2 O http://dharam939.blogspot.in

10. udihrN - 2 s>t&l)t sm)krN lKi[ an[ 50.0 mL ni 1.00 M KOH n[ tTAY krvi miT[ k[Tli m)l) l)Tr 2.00 M H 2 SO 4 ji[ea[ t[ gNi[. ___H 2 SO 4 + ___KOH ___K 2 SO 4 + H 2 O 1)12.5 mL 2) 50.0 mL3) 200. mL http://dharam939.blogspot.in

11. uk[l -2 50.0 mL 1.00 M KOH n[ tTAY krvi miT[ k[Tli m)l). 2.00 M H 2 SO 4 50.0 mL 1.00 M KOH n[ tTAY krvi miT[ k[Tli m)l). 2.00 M H 2 SO 4 ji[ea[? H 2 SO 4 + 2KOH K 2 SO 4 + 2H 2 O 0.0500 L x 1.00 mole KOH x 1 mole H 2 SO 4 x 0.0500 L x 1.00 mole KOH x 1 mole H 2 SO 4 x 1 L 2 mole KOH 1 L 2 mole KOH 1 L x 1000 mL = 12.5 mL 1 L x 1000 mL = 12.5 mL 2 mole KOH 1 L 2 mole KOH 1 L http://dharam939.blogspot.in

12. udihrN -3 25 mL fi[Afi[r)k a[(sD n[ 40. mL ni 1.5 M NaOH vD[ tTAY krvimi> aiv[ C[. ti[ fi[Afi[r)k a[(sD ni WivNni[ aN&Bir Si[Fi[. 3NaOH + H 3 PO 4 Na 3 PO 4 + 3H 2 O 1) 0.45 M2) 0.80 M3) 7.2 M http://dharam939.blogspot.in

13. uk[l - 3 0.040 L x 1.5 mole NaOH x 1 mole H 3 PO 4 1 L 3 mole NaOH 1 L 3 mole NaOH x 1 = 0.80 mol/L = 0.80 M x 1 = 0.80 mol/L = 0.80 M 0.025 L 0.025 L http://dharam939.blogspot.in