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CHAPTERS 7 & 8 CHAPTERS 7 & 8 NETWORKS 1: 0909201-01 NETWORKS 1: 0909201-01 9 December 2002 – Lecture 8a ROWAN UNIVERSITY College of Engineering Professor Peter Mark Jansson, PP PE DEPARTMENT OF ELECTRICAL & COMPUTER ENGINEERING Autumn Semester 2002
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admin last week’s lab 5 due today, lab 6 is due next Monday hw 7 due wed, hw 8 due at final exam final exam: Next Wed 18 Dec 10:15am take – home portion? If yes, will be given Wed 11 Dec: due 18th
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admin continued next semester schedule: NOTE: electronics 1 and digital 1 are FULL semester courses beginning first day of the spring term ( see handout ) 21 Jan
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networks I Today’s learning objectives – common signal wave forms review capacitance and inductance op amps and RC circuits revisit op-amps w/ Dr. Schmalzel introduce first order circuits introduce concept of complete response
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common signal waveforms see table 8.2-1 for more detail (p.309) continuous (dc) step decaying exponential ramp pulse sinusoid
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series and parallel – C & L series – parallel –
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HANDY CHART ELEMENT CURRENTVOLTAGE
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some implications when the element (C or L) is in a steady-state condition: An inductor (L) acts as a short circuit to a constant (dc) current at its terminals A capacitor (C) acts as a open circuit to a constant (dc) voltage across its terminals
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solving circuits with C & L see problem 7.6-7 given:
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OP-AMP CIRCUITS WITH C & L _+_+ i1i1 i2i2 ioio vovo v2v2 v1v1 CfCf RiRi +–+– vsvs Node a
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QUIZ: Find v o = f(v s ) _+_+ i1i1 i2i2 ioio vovo v2v2 v1v1 RfRf +–+– vsvs Node a LiLi
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ANSWER TO QUIZ
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‘real’ op-amps revisited with Dr. Schmalzel op-amps with feedback loops
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IMPORTANT CONCEPTS FROM CH. 7 I/V characteristics of C & L energy storage in C & L writing KCL & KVL for circuits with C & L solving op-amp circuits with C or L at the input solving op-amp circuits with C or L in feedback loop per Dr. Schmalzel’s lecture
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new concepts from ch. 8 response of first-order circuits the complete response stability of first order circuits
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1st ORDER CIRCUITS WITH CONSTANT INPUT +–+– t = 0 R1R1 R2R2 R3R3 Cvsvs + v(t) -
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Thevenin Equivalent at t=0 + RtRt C +–+– V oc + v(t) - KVL i(t) + -
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SOLUTION OF 1st ORDER EQUATION
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SOLUTION CONTINUED
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WITH AN INDUCTOR +–+– t = 0 R1R1 R2R2 R3R3 Lvsvs i(t)
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Norton equivalent at t=0 + RtRt I sc + v(t) - L i(t) KCL
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SOLUTION
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HANDY CHART ELEMENT CURRENTVOLTAGE
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IMPORTANT CONCEPTS FROM CHAPTER 8 determining Initial Conditions setting up differential equations solving for v(t) or i(t)
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