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Introduction - slide 3 Temasek Secondary School Preliminary Examination 1999 Paper 1 8, 11 Paper 2 5ai, 5bii, 6ci, 6ciii,7a Thanks for viewing our presentation!
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Are you daring? Do you enjoy a challenge? If you are, then try out the mathematical games that we have prepared for you! GAME S PLS: CLICK ON THE HEART TO KNOW THE ANSWER!
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The figure is a sketch of the graph y=x(x-2)(3-x). Find the equation of the tangents at x=2 and x=3.
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y=-x 3 +5x 2 -6x when x=2, y=0, when x=3, y=0 y=x(x-2)(3-x) Equation of the tangent at (2,0) is y=2x-4 Equation of the tangent at (3,0) is y=-3x+9
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Find the area of the region enclosed by the curve and the two tangents at x=2 and x=3.
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To find the intersecting point of the two tangents, 2x-4=-3x+9 The intersecting point of the two tangents is (2.6,1.2).
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Area of the triangle Area under the curve
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Area of the triangle Area under the curve The area of the region enclosed by the curve and the two tangents at x=2 and x=3
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A particle P travels in a straight line so that its distance, S m, from a fixed a point O is given by Where t is the time in seconds measured from the start of the motion. Calculate the velocity of P when it is next at its starting point. 11
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When t=0, S=18 When S=18, t 2 -8t=0 t=0 or t=8 When t=8, the velocity of P when it is next at its starting point is
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Cos(2x-30 o )=sin2x
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Cos(2x-30 o )=cos(90 o- 2x) 2x-30 o = 90 o- 2x or 360 o +90 o- 2x or 720 o +90 o -2x or 1080 o +90 o- 2x 4x=120 o or 480 o or 840 o or 1200 o x= 30 o or 120 o or 210 o or 300 o
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Given that find in terms of p, for
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Given that V=12-12sin6t Find the range of values of V.
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Graph of V=12-12sin6t Range of v is 0 v 24 V=12-12sin 6t
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The distance travelled by the particle from O to the first instance at which it is at rest. V=12-12sin6t
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Sin6t=1 The distance travelled= When V=0, 12-12sin6t=0
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Find
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Where c is a constant
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