1. Quadratic Cliff Jumping Deann Anguiano Laura Moore-Mueller Russ Ballard Lake Chelan Conference 2008

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3. 3 Motion along a curved path What is happening The scene is messy What can be assumed What are the concepts

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9. 9 Why use projectile motion? Position vs. position graph Apply regression curve First few points do not work

10. May 2, 2008 10 Which points? Depends on what’s occurring Symmetry Vertex

11. May 2, 2008 11 Hot wheels Instructions –You have a sheet for the activity Data gathering –Gather as much data as possible –Three to four runs is a minimum

12. May 2, 2008 12 Challenge cup Team Crimson –Given a height you pick position Team Silver –Given a position you pick the height

13. May 2, 2008 13 Tossing the ball Watch the ball being tossed into the air Plot a d vs. t graph of the motion on your ball toss graph

14. May 2, 2008 14 Tossing the ball Exchange with a neighbor Answer questions based on graph in front of you How long was the ball in the air? Is the vertical distance as the ball travels upward the same or different as the vertical distance traveled downward? Is the time from the launch to the vertex the same as the vertex to the ground?

15. May 2, 2008 15 Why use distance vs time? Return the graph to the owner and owners now reflect –What kind of motion did I graph? –If it was incorrect why would the graph mislead a student? –If necessary redraw the graph on the opposite side of the paper.

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17. May 2, 2008 17 What is the motion? In the horizontal? In the vertical? Motion is parametric Look at the vertical motion

18. May 2, 2008 18 Horizontal motion

19. May 2, 2008 19 Vertical motion

20. May 2, 2008 20 a(t) = -9.81 m/sec 2 v(t) = area in graph in the rectangle Therefore v(t) = -9.81m/s 2 * t(s) Or the ball is traveling at -9.81*t m/s after t seconds

21. May 2, 2008 21 Initial velocity is zero at the top After one second it = -9.81 m/s Slope is constant so the area under the curve is a triangle =½ base * height =½ t(s) * (-9.81*t m/s) = -4.9 t 2 (m) I second Velocity = -9.81 m/s Velocity(m/s) time (s)

22. May 2, 2008 22 Y = At^2 + Bt +C A:-4.844 B:6.513 C:-1.168

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24. May 2, 2008 24 T3 clip Calculate if the TX will make to the hearse roof. Distance and speed of hearse 20 m/s 26 m travel Distance vertical that TX will fall 8.3 m Distance at speed horizontal she is traveling 7.9 m/s 10.3 m

25. May 2, 2008 25 Vernier LoggerPRo Hand out Vernier LoggerPRo profile

26. May 2, 2008 26 Video Analysis Demo video analysis of the clip if time

27. All info is located at russballard.com/workshop/chelan conference 2008

28. Questions?