1. An Application Activity
Projectile Motion
An Application Activity

2. Projectile Motion
When an object is dropped, it falls a distance of {(-16feet) or (-9.81meters)}t2 in t seconds. This is the force of gravity on any given object.

3. Projectile Motion
What happens to a projectile that is launched with some initial vertical velocity, v0, (measured in distance units per second at some initial height h0 (measured in distances units).

4. Projectile Motion
Horizontal motion is uniform, and independent of vertical motion.
Vertical motion is free fall, and independent of horizontal motion.

5. Projectile Motion
You know that a dropped object falls a distance of 16t2 feet in t seconds. When an object is not simply released but is thrown or launched, it is called a projectile. What happens to a projectile that is launched with some initial vertical velocity, Vo (measured in feet per second), at some initial height ho (measured in feet).

6. Projectile Motion
Without gravity to pull the projectile its height h Would increase according to the equation h = vo t + ho
With gravity, the projectile falls 16t2 feet in t seconds.
So the projectile’s height at any time t is given by
H = -16t2 + v0t + h0

7. Projectile Motion
For a tennis ball, a baseball, and a model rocket, Find,
the maximum height,
the time it reached that height and
the time the object returns to earth
given the following velocities and starting heights

8. h(t) = {(-16ft) or (-9.81m)}t2 + v0t + h0
Projectile Motion
h(t) = {(-16ft) or (-9.81m)}t2 + v0t + h0
Tennis ball
h0 = 0.8m, v0 =34.7m/sec
h0 = 1.0m, v0 =27.3m/sec
Baseball
h0 = 3.4ft., v0 =101mph
h0 = 2.7ft, v0=80.67ft/sec
Model Rocket
h0 = 0.4ft., v0 =670ft/sec
h0 = 2.4ft., v0 =490ft/sec