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CSCE 441: Keyframe Animation/Smooth Curves (Cont.) Jinxiang Chai
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Key-frame Interpolation Given parameter values at key frames, how to interpolate parameter values for inbetween frames. θ t
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Key-frame Interpolation Given parameter values at key frames, how to interpolate parameter values for inbetween frames. t θ
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Key-frame Interpolation Given parameter values at key frames, how to interpolate parameter values for inbetween frames. t θ Nonlinear interpolation
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Review: Natural cubic cruves
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Review: Natural cubic curves Properties: - Go through four control points - not good for local control
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Review: Hermite Curves P1P1 R1R1 P4P4 R4R4 P 1 : start position P 4 : end position R 1 : start derivative R 4 : end derivative
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Review: Hermite Curves P1P1 R1R1 P4P4 R4R4
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P1P1 R1R1 P4P4 R4R4 Herminte basis matrix
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Review: Hermite Curves P1P1 R1R1 P4P4 R4R4 Herminte basis matrix
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Review: Hermite Curves P1P1 R1R1 P4P4 R4R4
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P1P1 R1R1 P4P4 R4R4
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P1P1 R1R1 P4P4 R4R4
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P1P1 R1R1 P4P4 R4R4
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P1P1 R1R1 P4P4 R4R4 Hermite basis functions
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Review: Hermite Curves P1P1 R1R1 P4P4 R4R4 basis function 1basis function 2basis function 3 basis function 4
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Review: Hermite Curves P1P1 R1R1 P4P4 R4R4 *P 1 *P 4 *R 1 *R 4 +++ =
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Review: Bezier Curves
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*v 0 *v 1 *v 2 *v 3 +++ =
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Cubic curves: Hermite curves: Bezier curves: Review: Different basis functions
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Complex curves Suppose we want to draw or interpolate a more complex curve
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Complex curves Suppose we want to draw or interpolate a more complex curve How can we represent this curve?
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Complex curves Suppose we want to draw a more complex curve Idea: we’ll splice together a curve from individual segments that are cubic Béziers
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Complex curves Suppose we want to draw or interpolate a more complex curve Idea: we’ll splice together a curve from individual segments that are cubic Béziers
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Splines A piecewise polynomial that has a locally very simple form, yet be globally flexible and smooth
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Splines There are three nice properties of splines we’d like to have - Continuity - Local control - Interpolation
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Continuity C 0 : points coincide, velocities don’t C 1 : points and velocities coincide What’s C 2 ? - points, velocities and accelerations coincide
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Continuity Cubic curves are continuous and differentiable We only need to worry about the derivatives at the endpoints when two curves meet
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Local control We’d like our spline to have local control - that is, have each control point affect some well-defined neighborhood around that point
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Local control We’d like our spline to have local control - that is, have each control point affect some well-defined neighborhood around that point
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Local control We’d like our spline to have local control - that is, have each control point affect some well-defined neighborhood around that point
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Interpolation Bézier curves are approximating - The curve does not (necessarily) pass through all the control points - Each point pulls the curve toward it, but other points are pulling as well - the curve is always located within the convex hull based on control points. Instead, we may prefer a spline that is interpolating - That is, that always passes through every control point
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B-splines We can join multiple Bezier curves to create B-splines Ensure C 2 continuity when two curves meet
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Derivatives at end points t=0 t=1
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Derivatives at end points t=0 t=1
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Derivatives at end points t=0 t=1
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Derivatives at end points t=0 t=1
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Derivatives at end points t=0 t=1
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Continuity in B splines Suppose we want to join two Bezier curves (V 0, V 1, V 2,V 3 ) and (W 0, W 1, W 2, W 3 ) so that C 2 continuity is met at the joint
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Continuity in B splines Suppose we want to join two Bezier curves (V 0, V 1, V 2,V 3 ) and (W 0, W 1, W 2, W 3 ) so that C 2 continuity is met at the joint
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Continuity in B splines Suppose we want to join two Bezier curves (V 0, V 1, V 2,V 3 ) and (W 0, W 1, W 2, W 3 ) so that C 2 continuity is met at the joint
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Continuity in B splines Suppose we want to join two Bezier curves (V 0, V 1, V 2,V 3 ) and (W 0, W 1, W 2, W 3 ) so that C 2 continuity is met at the joint
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Continuity in B splines Suppose we want to join two Bezier curves (V 0, V 1, V 2,V 3 ) and (W 0, W 1, W 2, W 3 ) so that C 2 continuity is met at the joint
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Continuity in B splines Suppose we want to join two Bezier curves (V 0, V 1, V 2,V 3 ) and (W 0, W 1, W 2, W 3 ) so that C 2 continuity is met at the joint
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Continuity in B splines What does this derived equation mean geometrically? - What is the relationship between a, b and c, if a = 2b - c? b is the middle point of a and c. w 2 =v 1 +4v 3 -4v 2
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de Boor points Instead of specifying the Bezier control points, let’s specify the corners of the frames that forms a B-spline These points are called de Boor points and the frames are called A-frames
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de Boor points What is the relationship between Bezier control points and de Boor points? Verify this by yourself!
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Building complex splines Constraining a Bezier curve made of many segments to be C 2 continuous is a lot of work - for each new segment we have to add 3 new control point - only one of the control points is really free B-splines are easier (and C 2 ) - First specify 4 vertices (de Boor points), then one per segment
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B splines properties √ Continuity √ Local control x Interpolation
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Catmull-Rom splines If we are willing to sacrifice C 2 continuity, we can get interpolation and local control. If we set each derivative to be a constant multiple of the vector between the previous and the next control points, we get a Catmull-Rom spline
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Catmull-Rom splines
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The segment is controlled by p 1,p 2,p 3,p 4 0.5
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Catmull-Rom splines The segment is controlled by p 1,p 2,p 3,p 4
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Catmull-Rom Splines The effect of t: how sharply the curve bends at the control points
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Catmull-Rom splines The segment is controlled by p 1,p 2,p 3,p 4
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Catmull-Rom splines From Hermite curves
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Catmull-Rom splines From Hermite curves
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Catmull-Rom splines From Hermite curves
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Catmull-Rom splines
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What do we miss?
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Catmull-Rom splines ? ?
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Catmull-Rom splines have C 1 continuity (not C 2 continuity) Do not lie within the convex hull of their control points.
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Catmull-Rom splines Catmull-Rom splines have C 1 continuity (not C 2 continuity) Do not lie within the convex hull of their control points.
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Catmull-Rom splines properties X Continuity (C 2 ) √ Local control √ Interpolation
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Catmull-Rome Splines for Kyeframe Interpolation Given a set of control points, interpolation splines are obtained by fitting the input points with a piecewise cubic polynomial curve that passes through every control point
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Catmull-Rome Splines for Kyeframe Interpolation Fit the interpolation function between each pair of control points with a cubic function p k-1 pkpk P k+1 P k+2
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Catmull-Rome Splines for Kyeframe Interpolation Fit the interpolation function between each pair of control points with the following cubic function: p k-1 pkpk P k+1 P k+2 0<=u<=1
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Outline Process of keyframing Key frame interpolation Hermite and bezier curve Splines Speed control
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Spline parameterization The spline is parameterized by u (0<=u<=1) and not by time t.
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Spline parameterization The spline is parameterized by u (0<=u<=1) and not by time t. Hard to deal with the questions like -What is the location of point p at time t -What is the velocity of point p at time t -What is the acceleration of point p at time t
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Spline parameterization Solution: reparameterize the curve in terms of t - express spline as a function of the arc length s: u=g(s) - express the arc length s as a function of t: s=f(t)
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Speed Control Click herehere
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Speed control Time warping function to control speed (mapping from the original time line to the output time line) - positive - monotonic; you cannot reverse the time s=f(t) Original timeline new timeline
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Speed control Simplest form is to have constant velocity along the path s=f(t)
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Speed control Simplest form is to have constant velocity along the path s=f(t) Which one is “speed up” or which one is “slow down”
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Speed control Simplest form is to have constant velocity along the path s=f(t) Slow down Speed up
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Speed control Assume that the motion slows down at the beginning and end of the motion curve s=f(t)
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Speed control Assume that the motion slows down at the beginning and end of the motion curve s=f(t) Adjust timing for each key frame
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Arc-length reparameterization Now we want a way to find u given a particular arclength s: u=g(f(t)) Not possible analytically for most curves (e.g. B- splines)
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Finite difference Sample the curve at small intervals of the parameter and determine the distance between samples Use theses distances to build a table of arclength for this particular curve: (u i,s i ) What’s parametric value for the arc length.08?
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Finite difference Sample the curve at small intervals of the parameter and determine the distance between samples Use theses distances to build a table of arclength for this particular curve: (u i,s i )
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Sample the curve at small intervals of the parameter and determine the distance between samples Use theses distances to build a table of arclength for this particular curve: (u i,s i ) Finite difference What’s parametric value for the arc length.08?
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Finite difference Sample the curve at small intervals of the parameter and determine the distance between samples Use theses distances to build a table of arclength for this particular curve: (u i,s i ) What’s parametric value for the arc length.08?
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Finite difference Sample the curve at small intervals of the parameter and determine the distance between samples Use theses distances to build a table of arclength for this particular curve: (u i,s i ) What’s parametric value for the arc length.05? A linear interpolation of 0.00 and 0.05
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Speed control recipe Given a time t, lookup the corresponding arclength S in the speed curve For S, look up the corresponding value of u in the reparameterization table Evaluate the curve at u to obtain the correct interpolated position for the animated object for the given time t
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