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 Objective: › Today I will be able to:  Calculate the molarity, molality, mole fraction and dilution for a solution  Analyze the effect of changing.

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Presentation on theme: " Objective: › Today I will be able to:  Calculate the molarity, molality, mole fraction and dilution for a solution  Analyze the effect of changing."— Presentation transcript:

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2  Objective: › Today I will be able to:  Calculate the molarity, molality, mole fraction and dilution for a solution  Analyze the effect of changing the temperature on the solubility of a compound  Evaluation/Assessment: › Informal Assessment – monitoring student interactions and questions as they complete the worksheets › Formal Assessment – analyzing student responses to the worksheet and exit ticket  Common Core Connection › Make sense of problem and persevere in solving them › Look for and make use of structure › Use appropriate tools strategically

3  Evaluate: Warm-Up (5 minutes)  Elaborate: Solutions Calculations Review ◦ 25 minutes  Explain: Solubility Curves (5 minutes)  Elaborate: Solubility Curve practice ◦ 15 minutes  Evaluate: Exit Ticket

4  Describe how to prepare 150 ml of a 1.2 M HCl solution from a 4.0 M HCl stock solution.

5  Today I will be able to: ◦ Calculate the molarity, molality, mole fraction and dilution for a solution ◦ Analyze the effect of changing the temperature on the solubility of a compound

6  Study for the Molarity, Molality, Mole Fraction and Dilution Quiz Tomorrow

7  Warm – Up  Concentration Practice  Solubility Curve Notes  Solubility Curve Practice  Exit Ticket

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9  Molarity (M) – moles of solute/liters of solution

10  Use Molarity calculations  Use a 1 L volumetric flask - calculate the formula weight of the compound - Dilute compound with water to the 1 L mark on the flask - Invert solution to mix - Creates a 1 M concentration solution

11  Dilution of a more concentrated solution to a less concentrated one  V old x M old = V new x M new

12  Molality = moles of solute/kg of solvent  Practice: What is the molality of a solution in which 3.0 moles of NaCl is dissolved in 1.5 kg of water?

13 Χ i = moles of i total moles

14  0.100 mole of NaCl is dissolved into 100.0 grams of pure H 2 O. What is the mole fraction of NaCl? ◦ Steps to solve the problem  Convert mass of H 2 O  moles of H 2 0  Add the moles of H 2 O and NaCl together to get the total number of moles in the solution  Divide the moles of NaCl by the total number of moles  Answer: 0.982  No units because it is a ratio!

15 Lets review some of the answers from the worksheets you all completed on Friday.

16 Think about: How does temperature affect solubility

17  What effect does increasing the temperature have on the solubility of a liquid? ◦ In general it increases  Why? ◦ Molecules move around more rapidly to dissolve quicker

18  Gas solubility decreases with temperature increase  Why does this happen? ◦ Molecules move faster, the gas particles escape the solution

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20 Complete the questions relating to the solubility curve. Ask Mr. Klotz for help if you have questions

21  What is the molality of a saturated KCl solution At 80 o C?


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