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int num = 22; if (num > 0) if (num % 5 == 0) System.out.println(num); else System.out.println(num + “ is negative”);

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Presentation on theme: "int num = 22; if (num > 0) if (num % 5 == 0) System.out.println(num); else System.out.println(num + “ is negative”);"— Presentation transcript:

1

2 int num = 22; if (num > 0) if (num % 5 == 0) System.out.println(num); else System.out.println(num + “ is negative”);

3 int num = 22;//Formatted to show computer processing if (num > 0)// True { if (num % 5 == 0)// False System.out.println(num); else // Default response System.out.println(num + “ is negative”); }

4 int num = 22;//How programmer intended formatting if (num > 0)// True { if (num % 5 == 0)// False System.out.println(num);}else System.out.println(num + “ is negative”);

5 int x = 30, y = 40; if (x >= 0) { if (x <= 100) { y = x * 3; if (y < 50) x /= 10; }else y = x * 2; }else y = -x;

6 int x = 30, y = 40; if (x >= 0)// True { if (x <= 100)// True { y = x * 3;// y = 90 if (y < 50)//False; x stays 30 x /= 10; }else y = x * 2; }else y = -x;

7 a. same b. abc c. ABC d. sameabc e. there is no output

8 a. same b. abc c. ABC d. sameabc e. there is no output

9 a. 14 b. 23 c. 34 d. 4 e. 12

10 a. 14 b. 23 c. 34 d. 4 e. 12


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