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The Most Interesting Statistics From 2014 | RealClearMarkets On average, children run a mile 90 seconds slower than their counterparts 30 years ago. Nine percent of Americans carry no cash, and half carry $20 or less. The average teen processes 3,700 texts per month. ….
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The Statisticians Objectives 1.Ask the right questions 2.Collect useful data 3.Summarize the data 4.Make decisions and generalizations based on the data 5.Turn the data and decisions into new knowledge
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Population uu u u u u u u u Sample u u u u u Inference Sampling Describe Probability The Frame
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Probability 1.What is the probability that a flipped coin comes up heads? 2.What is the probability of a randomly selected card being a king? 3.What is the chance of rolling a 3 or 4 on a die?
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Random Experiments Outcomes (minimal results) Events (A, B, C…) Sample Space (S)
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E1: Flip a coin once – Outcomes: T or H – Events: A={T} B={H} C={H or T} – S = {T,H}
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E2: Flip two coins -Outcomes: (H,H) or (H,T) or (T,H) or (T,T). -Events: -A: {One H, one T} = {(H,T), (T,H)} -B: {at least one H} = {(H,T),(T,H), (H,H)} - S = {(T,T); (T,H);(H,T); (H,H) }
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E3: Cast two dice Outcomes: (1,1) or (1,2) or … (6,6) Events: A = {(3,4)} B ={The sum is greater than 7} C = … S = {(1,1);(1,2); … ; (6,6)}
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Probability: classical definition All outcomes are equally likely P(A) = # outcomes in A Total # outcomes You can think of the classical definition of probability as a proportion
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E4. Draw a card A deck of 52 cards: S={all possible draws} # outcomes in S = 52 P(a King) = 4/52 = 1/13 P(a Heart) = 13/52 = ¼ P(king of Hearts)= 1/52
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Flip a Coin Three Times Outcomes HHH HHT HTH HTT THH THT TTH TTT 1.P(HHH) = 1/8 = 0.125 2.P(Two Heads) = 3.P(At least 2 Heads) = 3/8 = 0.375 4/8 = ½ = 0.5
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Roll Two Dice Outcomes: (1,1)(1,2)(1,3)(1,4)(1,5)(1,6) (2,1)(2,2)(2,3)(2,4)(2,5)(2,6) (3,1)(3,2)(3,3)(3,4)(3,5)(3,6) (4,1)(4,2)(4,3)(4,4)(4,5)(4,6) (5,1)(5,2)(5,3)(5,4)(5,5)(5,6) (6,1)(6,2)(6,3)(6,4)(6,5)(6,6) P(Sum =2) = 1/36 = 0.0278 P(Sum=9) = 4/36 = 1/9 = 0.111 P(Sum=7) = 6/36 = 1/6 = 0.167
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Simple Random Sample 1000 people in population, –250 prefer red to green –300 prefer green to red –The rest don’t care Random person –P(prefers green to red) = 300/1000 = 30% –P(don’t care) = 450/100 = 0.45
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Probability Properties 0 ≤ P(A) ≤ 1 P(A) = 0 → A is impossible P(S) = 1
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Probability: a general definition P(A) = Size of the Event A Size of the Sample Space S
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A S Venn diagrams
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Unequal Outcomes Assign a probability to each outcome. All probabilities ≥ 0. P(A) = sum P of each outcome in A All probabilities sum to 1. –P(S) = 1 All probabilities ≤ 1.
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Choose a Mascot OscarKermitElmoGrover P 0.10.30.2 0.4 P(Kermit or Elmo) = 0.3 + 0.2 = 0.5 P(Oscar or Kermit or Elmo) = 0.1 + 0.3 + 0.2 = 0.6 P(Grover) = 0.4
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OR Rule If A and B can’t both happen: P(A OR B) = P(A)+P(B) A and B are said to beMutually Exclusive
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A B S Mutually Exclusive
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A Å B = A and B cannot both happen Examples: A=“Draw a King” B = “Draw a Queen” A=“Roll a 3”B = “Roll an even number”
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E2: Flip two coins -A: {One H, one T} -P(A) = P[(H,T) OR (T,H)}] =1/4+1/4= 1/2 -B: {at least one H} -P(B) = P[(H,T) OR (T,H) OR (H,H)} = 3/4
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Complements Complement of A All outcomes not in A AcAc P(A c ) = 1 – P(A) P(Drawing a card other than an Ace) =1 – 1/13 = 12/13
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E2: Flip two coins -B: {at least one H} -P(B) = P[(H,T) OR (T,H) OR (H,H)} = 3/4 Or we could use the complement: - B C = {no H} - P(B C ) = P(T,T) = ¼ → P(B) = 1- P(B C ) = 1-1/4=3/4
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AND Rule If A and B are Independent P(A AND B) = P(A)P(B) Independent if A occurs, No affect on if B occurs Examples H and then H 6 and then 2
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A and B A B A Å B
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Successive Events P(Heads and then Tails) = P(Roll ) = P(Roll 1 and then an even number) =
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Probability Rules Not ) 1 - Probability OR & Mutually Exclusive ) Add AND & Independence ) Multiply
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OR Rule Mutually Exclusive –Events contain no common outcomes –Intersection is empty –They can’t both happen For mutually exclusive events A,B P(A or B) = P(A) + P(B)
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Mutually Exclusive Outcomes are mutually Exclusive –Cast a die: only one number can happen –Flip a coin: only one face shows up Mutually Exclusive events are NOT independent –If A and B are mutually exclusive they cannot both happen → P(A AND B) = 0
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2. OR Rule Roll 2 dice, P(Sum is 7 or 9) = 1/6 + 1/9 = 5/18 Flip three coins P(1 H or 3 H) = 3/8 + 1/8 = ½ Draw a card P(K or Q) = 1/13 + 1/13 = 2/13 P(Diamond or Heart) = ¼ + ¼ = 1/2 P(K or Diamond) = ????
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General OR Rule For any events A, B P(A or B) = P(A) + P(B) – P(A and B)
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A OR B A B A Å B S
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P(King or Heart) P(King) = 4/52 = 1/13 P(Heart) = 13/52 = ¼ P(King and Heart) = P(King of Hearts) = 1/52 P(King or Heart) = = P(King) + P(Heart) – P(King and Heart) =4/52 + 13/52 – 1/52 = 16/52 = 4/13
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Example S A B P(A) = 1/3, P(B)= ¼ and P(A and B) =1/6 Compute P(A c or B)
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P(A c or B)? Use general OR rule –P(A c or B) = P(A c ) + P(B) – P(A c and B) Note that –P(A c )= 1- P(A) = 1-1/3 = 2/3 –P(B) = ¼ –P(A c and B)? Not independent
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S A ACAC
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S A A C and B P(A c and B) = P(B) – P(A and B) P(B) = P(A c and B) + P( A and B) Since they are mutually exclusive Then
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Finally –P(A c )= 1- P(A) = 1-1/3 = 2/3 –P(B) = ¼ –P(A c and B) = P(B)-P(A and B) = ¼ - 1/6 = 1/12 From which P(A c or B)= 2/3 + ¼ -1/12 = 5/6
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