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By: Jeffrey Bivin Lake Zurich High School jeff.bivin@lz95.org
Math Induction By: Jeffrey Bivin Lake Zurich High School Last Updated: March 30, 2011
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Before we begin…… If Pk = 1 + 5 + 9 + . . . + (4k-3) find Pk+1.
Pk+1 = (4k-3) + (4(k+1) – 3) Pk+1 = (4k-3) + (4k+1)
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Before we begin…… If Pk = k2(k+1)2 find Pk+1.
Pk+1 = (k+1)2(k+1+1)2 = (k+1)2(k+2)2
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The Principle of Math Induction
Let Pn be a statement involving the positive integer n. If 1. P1 is true the truth of Pk implies the truth of Pk+1 for every positive k then Pn must be true for all positive integers n. To apply the Principle of Math Induction, you need to be able to determine the statement Pk+1 for a given statement Pk. To determine Pk+1, substitute k+1 for k in the statement Pk. Direct Quote: Precalculus with Limits – A Graphin Approach by Larson, Hostetler & Edwards © 2005 by Houghton Mifflin Company
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Induction – A three step process
Step 1: Show P1 is true APPROACH THE Step 2: Assume Pk is true Step 3: Prove Pk+1 is true A “Bivinism”
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Prove: Show P1: Assume Pk: Prove Pk+1: Q.E.D.
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 1
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 2
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 3
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 4
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Prove: Show P1: Assume Pk: Prove Pk+1: Q.E.D.
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Worksheet Exercise # 5
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 6
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 7
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 8
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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Worksheet Exercise # 9
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Prove: Show P1: Assume Pk: Prove Pk+1:
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We need a common denominator to add the fractions.
Prove Pk+1: We need a common denominator to add the fractions.
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Prove Pk+1: We see that a factor of (k+1) is in the denominator on the left that is not on the right. Maybe the numerator has a (k+1) factor that will cancel with it. We will use synthetic division to check. 3 14 19 8 -1 -3 -11 -8 11 Q.E.D.
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Worksheet Exercise # 10
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Prove: Show P1: Assume Pk: Prove Pk+1:
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Prove Pk+1: Q.E.D.
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