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Rolling, torque, and angular momentum
Chapter 11 Rolling, torque, and angular momentum
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ds/dt = d(θR)/dt = R dθ/dt vcom = ds/dt = ωR
Smooth rolling Smooth rolling – object is rolling without slipping or bouncing on the surface Center of mass is moving at speed vcom Point P (point of momentary contact between two surfaces) is moving at speed vcom s = θR ds/dt = d(θR)/dt = R dθ/dt vcom = ds/dt = ωR
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Rolling: translation and rotation combined
Rotation – all points on the wheel move with the same angular speed ω Translation – all point on the wheel move with the same linear speed vcom
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Rolling: pure rotation
Rolling can be viewed as a pure rotation around the axis P moving with the linear speed vcom The speed of the top of the rolling wheel will be vtop = (ω)(2R) = 2(ωR) = 2vcom
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Chapter 11 Problem 2
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fs opposes tendency to slide
Friction and rolling Smooth rolling is an idealized mathematical description of a complicated process In a uniform smooth rolling, P is at rest, so there’s no tendency to slide and hence no friction force In case of an accelerated smooth rolling acom = α R fs opposes tendency to slide
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Rolling down a ramp Fnet,x = M acom,x fs – M g sin θ = M acom,x R fs = Icom α α = – acom,x / R fs = – Icom acom,x / R2
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Torque revisited Using vector product, we can redefine torque (vector) as:
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Angular momentum Angular momentum of a particle of mass m and velocity with respect to the origin O is defined as SI unit: kg*m2/s
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Newton’s Second Law in angular form
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Angular momentum of a system of particles
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Chapter 11 Problem 33
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Angular momentum of a rigid body
A rigid body (a collection of elementary masses Δmi) rotates about a fixed axis with constant angular speed ω Δmi is described by
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Angular momentum of a rigid body
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Conservation of angular momentum
From the Newton’s Second Law If the net torque acting on a system is zero, then If no net external torque acts on a system of particles, the total angular momentum of the system is conserved (constant) This rule applies independently to all components
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Conservation of angular momentum
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Conservation of angular momentum
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More corresponding relations for translational and rotational motion (Table 11-1)
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Chapter 11 Problem 51
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Answers to the even-numbered problems
Chapter 11: Problem 4 (a) 8.0º; (b) more
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Answers to the even-numbered problems
Chapter 11: Problem 18 (a) (6.0 N · m)ˆj + (8.0 N · m) ˆk; (b) (− 22 N · m)ˆi
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Answers to the even-numbered problems
Chapter 11: Problem 26 (a) (6.0 × 102 kg · m2/s) ˆk; (b) (7.2 × 102 kg · m2/s)ˆk
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Answers to the even-numbered problems
Chapter 11: Problem 32 (a) 0; (b) (−8.0N · m/s)tˆk; (c) − 2.0/√t ˆk in newton·meters for t in seconds; (d) 8.0 t−3 ˆk in newton·meters for t in seconds
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Answers to the even-numbered problems
Chapter 11: Problem 42 (a) 750 rev/min; (b) 450 rev/min; (c) clockwise
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