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Stage 6 Advanced Additive
Solve
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53 - 29 Summary of Strategies Tidy numbers using Compensation
Place Value Partitioning Reversibility 29 + ? = 53 Equal Additions
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Tidy Numbers using Compensation = 24
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Place Value Partitioning = 24
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53 – 29 Reversibility = 53
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Equal Additions 1 54 30 53 = 24 29
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Equal Additions 53 29 30 54
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53 - 29 Summary of Strategies Tidy numbers using Compensation
Place Value Partitioning Reversibility 29 + ? = 53 Equal Additions
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Possible Multiplicative Strategies
Tidy Numbers I know 5 x 40 = 200. 200 - (4x5) = 180. Place Value 5 x 30 = 150. And 5 x 6 = 30. So = 180 5 x 36 = Written Form 36 X 5 180 Doubling and Halving. Double 5= 10, half 36= 18. So 10 x 18 = 180
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Stage 7 Advanced Multiplicative
Solve 3 x 18
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3 x 18
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Types of Advanced Multiplicative Part-Whole Strategies 3x18
Rounding –(20x3)-(2x3) Adding – (12x3)+(6x3) Doubling – 2x(9x3) Proportional adjustment (e.g. doubling and halving) (9x6) Place vale partitioning (10x3) +(8x3)
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3 x 18 Tidy Numbers using Compensation 3 x 20 = 60 60 - (3 x 2) = 54
10 3 x 20 = 60 60 - (3 x 2) = 54
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3 x 18 Place Value Partitioning 10 3 x 10 = 30 = 54 3 x 8 = 24
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3 x 18 3 x 9 3 x 9
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Proportional Adjustment
6 x 9 = 54 3 x 18 6 x 9 x 2 ÷ 2
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Using Number Lines 3x18 Proportional Adjustment Place value
Tidy Numbers 54 A 30 54 B 54 60 C
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Possible Multiplicative Strategies
Tidy Numbers I know 5 x 40 = 200. 200 - (4x5) = 180. Place Value 5 x 30 = 150. And 5 x 6 = 30. So = 180 5 x 36 = Written Form 36 X 5 180 Doubling and Halving. Double 5= 10, half 36= 18. So 10 x 18 = 180
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Diagnostic Interview – Car Problem
Possible multiplicative part-whole strategies for the wheels problem include: 80 4 = 2- so 72 4 = 20 – (8 4) = 18 (compensation) 10 x 4 = – 40 = 32, 8 x 4 = 32, = 18, so 18 x 4 = 72 (reversibility and place-value partitioning); 9 x 8 = x 4 = 72 (doubling and halving) (Ministry of Education, 2005a)
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