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THE PHYSICS OF RADIOLOGY BASIC CONCEPTS PART Three BME College Sherman sheen
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Mass and energy Einstein’s theory E = m c 2 Energy corresponding to one electron: 1 kg m 2 S -2 = 1 joule Because:
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Mass and energy mass of one carbon atom = Example 1-7. Calculate the energy equivalent of 1 atomic mass unit (amu). Avogadro's number = 6.022045 ×10 23 carbon has a mass number of 12, it contains 12 amu Hence, the conversion of 1 amu to energy
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two important mass-to-energy conversion factors :
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Mass and velocity m 0, the rest mass 1/10 the velocity of light, increase in mass of 0.5% 98% of light (v/c = 0.98), 5 times of the rest mass
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Mass and velocity Kinetic Energy ElectronsProtons Total Energy (MeV) Velocity Relative to Vel. of Light Mass Relative to Rest Mass Velocity Relative to Vel. of Light Mass Relative to Rest Mass 10 keV 100 keV 200 keV 500 keV 1 MeV 2 MeV 5 MeV 10 MeV 20 MeV 50 MeV 100 MeV 0.521 0.1950 1.020 0.611 0.5483 1.196 0.711 0.6954 1.392 1.011 0.8629 1.979 1.511 0.9411 2.957 2.511 0.9791 4.916 5.511 0.9957 10.79 10.511 0.998817 20.58 20.511 0.999689 40.16 50.511 0.999949 99.01 100.511 0.999987 192.31 0.0046 1.0000 0.0147 1.0001 0.0208 1.0002 0.0326 1.0005 0.0465 1.0011 0.0657 1.002 0.1026 1.0053 0.1451 1.0107 0.2033 1.0213 0.3141 1.0533 0.4283 1.1066
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