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Form 1 Mathematics Chapter 10
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Lesson requirement Textbook 1B Workbook 1B Notebook Before lessons start Desks in good order! No rubbish around! No toilets! Keep your folder at home Prepare for Final Exam
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Missing HW Detention Ch 10 SHW(I) 28 May (Tue) Ch 10 SHW(II) 31 May (Fri) Ch 10 SHW(III) 31 May (Fri) Ch 10 OBQ 31 May (Fri) Ch 10 CBQ 4 June (Tue)
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The sum of the interior angles of any triangle is 180°. i.e.In the figure, a + b + c = 180 °. [Reference: sum of ]
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The sum of angles at a point is 360 °. e.g. In the figure, a + b + c + d = 360°. [Reference: s at a pt.]
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The sum of adjacent angles on a straight line is 180 °. e.g. In the figure, a + b + c = 180°. [Reference: adj. s on st. line]
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When two straight lines intersect, the vertically opposite angles formed are equal. i.e. In the figure, a = b. [Reference: vert. opp. s]
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The corresponding angles formed by parallel lines and a transversal are equal. i.e. In the figure, if AB // CD, then a = b. [Reference: corr. s, AB // CD]
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The alternate angles formed by parallel lines and a transversal are equal. i.e. In the figure, if AB // CD, then a = b. [Reference: alt. s, AB // CD]
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The sum of the interior angles of parallel lines on the same side of the transversal is 180 °. i.e. In the figure, if AB // CD, then a + b = 180°. [Reference: int. s, AB // CD]
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Example 6: p q r In the figure, AB, QR and CD are parallel lines, while PQ and RS are another pair of parallel lines. If RSA = 66°, find QPD. Using the notation in the figure, r + 66° = 180° (int. s, AD // QR) r = 114° ∵ q = r (alt. s, PQ // RS) ∴ q = 114° ∵ p + q = 180° (int. s, QR // CD) p + 114° = 180° p = 66° ∴ QPD = 66°
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Example 7: Find the unknown angle x in the figure. Draw the straight line AT such that AT // PQ. Since PQ // NS, we have AT // NS. Using the notation in the figure, y + 145 ° = 180° (int. s, PQ // AT) ∴ y = 35° 67° + x + y = 180° (int. s, NS // AT) 67° + x + 35° = 180° x = 78° A y
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Pages 154 – 155 of Textbook 1B Questions 4 – 25 Pages 59 – 61 of Workbook 1B Question 1 - 8
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The conditions needed for two lines to be parallel: 1. If the corresponding angles formed by two lines and a transversal are equal, then the two lines are parallel. i.e.In the figure, if a = b, then AB // CD. [Reference: corr. s equal]
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The conditions needed for two lines to be parallel: 2. If two lines are cut by a transversal and the alternate angles are equal, then the two lines are parallel. i.e.In the figure, if a = b, then AB // CD. [Reference: alt. s equal]
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The conditions needed for two lines to be parallel: 3. If two lines are cut by a transversal and the interior angles on the same side of the transversal are supplementary, then the two lines are parallel. i.e.In the figure, if a + b = 180°, then AB // CD. [Reference: int. s supp.]
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Example 1: Are the lines AB and CD in the figure parallel to each other? ∵ BFG = DGH = 75 ° ∴ AB // CD ( corr. s equal )
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Example 2: Determine if lines AC and DF as shown in the figure are parallel. ∵ ABE = FEB = 125 ° ∴ AC // DF (alt. s equal)
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Example 3: Determine if lines AB and DC as shown in the figure are parallel. ∵ ABC + DCB ∴ AB // DC (int. s supp.) = 150° + 30° = 180°
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Example 4: Determine if lines DE and FG as shown in the figure are parallel. FCB + 35° + 50° = 180° (adj. s on st. line) ∴ FCB = 180° – 35° – 50° = 95° ∵ DBA = FCB = 95° ∴ DE // FG (corr. s equal)
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Example 5: In the figure, AB // CD, ABC = 40 °, BCD = 2p, CDE = 3p – 20°. (a) Find p. (b) Is it true that BC // DE? Give reasons. (a) 2p = 40° (alt. s, AB // CD) p = 20° (b) BCD = 2p = 40° CDE = 3p – 20° = 3 20° – 20° = 40° ∵ BCD = CDE = 40° ∴ BC // DE (alt. ∠ s equal)
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Missing HW Detention Ch 10 SHW(I) 28 May (Tue) Ch 10 SHW(II) 31 May (Fri) Ch 10 SHW(III) 31 May (Fri) Ch 10 OBQ 31 May (Fri) Ch 10 CBQ 4 June (Tue)
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Enjoy the world of Mathematics! Ronald HUI
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