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Chemistry Chapter 12 Review Game. Balancing Chemical Equations Stoich #1 (easy) Stoich #2 (more difficult) % Yield 1 point 1 point 1 point 1 point 1 point.

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Presentation on theme: "Chemistry Chapter 12 Review Game. Balancing Chemical Equations Stoich #1 (easy) Stoich #2 (more difficult) % Yield 1 point 1 point 1 point 1 point 1 point."— Presentation transcript:

1 Chemistry Chapter 12 Review Game

2 Balancing Chemical Equations Stoich #1 (easy) Stoich #2 (more difficult) % Yield 1 point 1 point 1 point 1 point 1 point 1 point 1 point 1 point 2 points 2 points 2 points 2 points 2 points 2 points 2 points 2 points 3 points 3 points 3 points 3 points 3 points 3 points 3 points 3 points 4 points 4 points 4 points 4 points 4 points 4 points 4 points 4 points 5 points 5 points 5 points 5 points 5 points 5 points 5 points 5 points

3 Calcium carbonate reacts with phosphoric acid to produce calcium phosphate, carbon dioxide and water. 1 pointCheck

4 What is… 3 CaCO 3 + 2 H 3 PO 4  Ca 3 (PO4) 2 + 3 CO 2 + 3 H 2 O? 1 point Back to Category Slide

5 Iron (III) sulfide reacts with oxygen to form iron (III) oxide and sulfur dioxide. 2 pointsCheck

6 What is… 4 FeS 2 + 11 O 2  2 Fe 2 O 3 + 8 SO 2 ? 2 points Back to Category Slide

7 Ammonium nitrate decomposes to nitrogen, water and oxygen. 3 pointsCheck

8 What is… 2 NH 4 NO 3  2 N 2 + 4 H 2 O + O 2 ? 3 points Back to Category Slide

9 Manganese oxide reacts with potassium hydroxide, oxygen and chlorine to form potassium permanganate, potassium chloride and water. 4 pointsCheck

10 What is … 2 MnO 2 + 4 KOH + O 2 + Cl 2  2 KMnO 4 + 2 KCl + 2 H 2 O? 4 points Back to Category Slide

11 Nitric acid and zinc react to form zinc nitrate, ammonium nitrate and water. 5 pointsCheck

12 5 points Back to Category Slide What is… 4 Zn + 10 HNO 3  4 Zn(NO 3 ) 2 + NH 4 NO 3 + 3 H 2 O?

13 This allows you to convert from substance A to substance B. 1 pointCheck

14 What is mole to mole ratio? 1 point Back to Category Slide

15 N 2 + 3 H 2  2 NH 3 The number of moles of H 2 I started with if I have 4.8 mol of ammonia 2 pointsCheck

16 What is 7.2 mol of H 2 ? 2 points Back to Category Slide

17 N 2 + 3 H 2  2 NH 3 The number of H atoms in ammonia if I have 28.3 grams of H 2. 3 pointsCheck

18 What is 1.70 x 10 25 H atoms? 3 points Back to Category Slide

19 N 2 + 3 H 2  2 NH 3 23.9 g of ammonia are produced. The volume of nitrogen gas (assume STP). 4 pointsCheck

20 What is 15.7 liters of N 2 ? 4 points Back to Category Slide

21 N 2 + 3 H 2  2 NH 3 I have 140,000 H atoms. The number of ammonia molecules I can produce with excess nitrogen. 5 pointsCheck

22 What is 47,000 ammonia molecules? 5 points Back to Category Slide

23 Use the following equation for #’s 2-5 2 C 2 H 2 + 5 O 2  4 CO 2 + 2 H 2 O 1 pointCheck

24 Use the following equation for #’s 2-5 2 C 2 H 2 + 5 O 2  4 CO 2 + 2 H 2 O 1 point Back to Category Slide

25 2.0 g of acetylene react with 6.0 g of oxygen. This is my limiting reactant. 2 pointsCheck

26 What is oxygen? 2 points Back to Category Slide

27 The number of grams of water that are produced when 2.0 g of C 2 H 2 react with 6.0 g of O 2. 3 pointsCheck

28 3 points Back to Category Slide What is 1.4 grams of water?

29 The number of acetylene molecules we started with if we produced 28.7 g of CO 2. 4 pointsCheck

30 4 points Back to Category Slide What is 1.96 x 10 23 molecules of C 2 H 2 ?

31 1,500 mL of acetylene react with excess oxygen. The number of liters of carbon dioxide that are produced. 5 pointsCheck

32 What is 3.0 liters of carbon dioxide? 5 points Back to Category Slide

33 The formula for % yield. 1 pointCheck

34 What is… (Actual / Theoretical) x 100? 1 point Back to Category Slide

35 If 15.0 g of nitrogen reacts with 15.0 g of hydgrogen, 10.5 g of ammonia is produced. The percent yield of this reaction. 2 pointsCheck

36 What is 57.7%? 2 points Back to Category Slide

37 Three reasons % yield can’t be more than 100%. 3 pointsCheck

38 What is impure reactants, competing side reactions, and human error? 3 points Back to Category Slide

39 The % yield when a test yields 12.3 mg of product A. According to the book, it should have yielded 0.133 dg. 4 pointsCheck

40 What is 92.5%? 4 points Back to Category Slide

41 The amount of product that needs to be made in a lab with a 95.5% yield. Assume a theoretical yield of 23.9 grams. 5 pointsCheck

42 What is 22.8 grams? (actual) 5 points Back to Category Slide

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