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Solve each equation. 1. 3x +5 = 17 2. 4x + 1 = 2x – 3 3. (x + 7)(x – 4) = 0 4.x 2 – 11x + 30 = 0 ALGEBRA O.T.Q.

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Presentation on theme: "Solve each equation. 1. 3x +5 = 17 2. 4x + 1 = 2x – 3 3. (x + 7)(x – 4) = 0 4.x 2 – 11x + 30 = 0 ALGEBRA O.T.Q."— Presentation transcript:

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2 Solve each equation. 1. 3x +5 = 17 2. 4x + 1 = 2x – 3 3. (x + 7)(x – 4) = 0 4.x 2 – 11x + 30 = 0 ALGEBRA O.T.Q.

3 HOMEWORK QUESTIONS???

4 10.4 Solving Equations Containing

5 To solve a radical you need to isolate the variable on one side of the equation. EX: 1 Factor out the GCF Subtract x√6 Divide both sides by (1 - √6) Continues on next slide…

6 Multiply by conjugate EX: 1 continued

7 Don’t forget to check your work. Substitute 1 + √6 in for x

8 Let’s solve another example together. EX: 2 Square each side. Then F.O.I.L. the right side Divide both sides by 6 Continued on next slide Subtract 19n and add 20

9 Square both sides again F.O.I.L. the left side Subtract 19n and add 29 Factor and solve for n Continued on next slide EX: 2 continued

10 Check: n=2 Since the root of x=2 does not check, it is called an extraneous solution.

11 Check : n = 27 The solution is n=27

12 SUMMARY

13 CLASSWORK HOMEWORK Pages 644 – 645 #’s 2, 4, 6, 10 – 28 even, 31 Pages 646 #’s 39, 40, 44, 50, 66


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