1. Stoichiometry

2. Problem If 16.8g of CO is mixed under high pressure with 1.78g of H 2. What is the mass of ethanol (CH 3 OH) will be produced? If 16.8g of CO is mixed under high pressure with 1.78g of H 2. What is the mass of ethanol (CH 3 OH) will be produced?

3. What do you do first? Balance the equation Balance the equation CO g to methanol moles CO g to methanol moles H 2 g to methanol moles H 2 g to methanol moles

4. CORRECT! CO+H 2  CH 3 OH CO+H 2  CH 3 OH Which equation balances the reaction? CO+2H 2  2CH 3 OH CO+2H 2  CH 3 OH 3CO+3H 2  2CH 3 OH Which equation balances the reaction? CO+2H 2  2CH 3 OH CO+2H 2  CH 3 OH 3CO+3H 2  2CH 3 OH

5. INCORRECT! Remember that you need to have both sides of the reaction equal before you can make an equation Remember that you need to have both sides of the reaction equal before you can make an equation Try Again Try Again

6. CORRECT CO+2H 2  CH 3 OH CO+2H 2  CH 3 OH What is next? Convert everything to moles Convert everything to grams What is next? Convert everything to moles Convert everything to grams leave everything as it is leave everything as it is

7. INCORRECT TRY AGAIN

8. INCORRECT! Remember that you need to have both sides of the reaction equal before you can make an equation Remember that you need to have both sides of the reaction equal before you can make an equation Try Again Try Again

9. Correct

10. SETTING UP THE EQUATIONS which is correct?

11. SETTING UP THE EQUATIONS

12. Which element is limiting? 16.8gCo = 9.14gCH 3 OH 1.78gH 2 = 14.12gCH 3 OH CoCo H 2 H 2 CoH 2

13. INCORRECT, remember that the smaller number symbolizes a limiting reactant. And larger number will have an excessive amount

14. Which element is excessive? 16.8gCo = 9.14gCH 3 OH 1.78gH 2 = 14.12gCH 3 OH CoCo H 2 H 2 CoH 2

15. CONGRATULATIONS You now know how to do stoichiometry You now know how to do stoichiometry

16. INCORRECT

17. INCORRECT