Download presentation
Presentation is loading. Please wait.
Published byRebecca Long Modified over 8 years ago
1
Heating curves and H temperature added energy
2
Heating curves and H temperature added energy solidliquidgas
3
Heating curves and H temperature added energy melting/ freezing pt solidliquidgas
4
Heating curves and H temperature added energy melting/ freezing pt boiling/ cond. pt solidliquidgas
5
Heating curves and H temperature added energy melting/ freezing pt boiling/ cond. pt solidliquidgas melting/freezing occurring here boiling/condensing occurring here
6
How is the total enthalpy change ( H) calculated for a substance whose temperature change includes a change in state?
7
temperature added energy t of solid absorbing energy
8
temperature added energy = m x C solid x t
9
temperature added energy = m x C solid x t the energy absorbed as a solid melts becomes potential energy, so no t
10
temperature added energy H = H fus x # mols = m x C solid x t
11
temperature added energy H = H fus x # mols t of liquid absorbing energy = m x C solid x t
12
temperature added energy H = H fus x # mols = m x C liquid x t = m x C solid x t
13
temperature added energy H = H fus x # mols the energy absorbed as a liquid boils becomes potential energy, so no t = m x C liquid x t = m x C solid x t
14
temperature added energy H = H fus x # mols H = H vap x # mols = m x C liquid x t = m x C solid x t
15
temperature added energy H = H fus x # mols H = H vap x # mols t of gas absorbing energy = m x C liquid x t = m x C solid x t
16
temperature added energy H = H fus x # mols H = H vap x # mols = m x C gas x t = m x C liquid x t = m x C solid x t
17
temperature added energy H = H fus x # mols H = H vap x # mols = m x C gas x t = m x C liquid x t = m x C solid x t
18
temperature added energy H = H fus x # mols H = H vap x # mols = m x C gas x t = m x C liquid x t = m x C solid x t The H of any substance being heated will be the sum of the H of any t occurring plus H of any phase change occurring
19
temperature added energy = H fus x # mols = H vap x # mols = m x C gas x t = m x C liquid x t = m x C solid x t The H of any substance being heated will be the sum of the H of any t occurring plus H of any phase change occurring
20
temperature added energy H = H fus x # mols H = H vap x # mols = m x C gas x t = m x C liquid x t = m x C solid x t EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C?
21
temperature added energy -20 o C 0 o C 50 o C EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C?
22
temperature added energy EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? -20 o C 0 o C 50 o C use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C
23
temperature added energy -20 o C 0 o C 50 o C H = H fus x # mols = m x C liquid x t = m x C solid x t EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C
24
temperature added energy -20 o C 0 o C 50 o C H = H fus x # mols = 10g x 2.1 J/g o C x 20 o C EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C = m x C liquid x t
25
temperature added energy -20 o C 0 o C 50 o C H =10 g x 1mol/18g x 6.01kJ/mol = 10g x 2.1 J/g o C x 20 o C H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C = m x C liquid x t
26
temperature added energy -20 o C 0 o C 50 o C = 10g x 4.186 J/g o C x 50 o C = 10g x 2.1 J/g o C x 20 o C H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C
27
temperature added energy -20 o C 0 o C 50 o C = 10g x 4.186 J/g o C x 50 o C = 10g x 2.1 J/g o C x 20 o C H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C total H = + H 2 +
28
temperature added energy -20 o C 0 o C 50 o C = 10g x 2.1 J/g o C x 20 o C H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C total H = + H 2 + = 420 J + 3340 J + 2093 J = 10g x 4.186 J/g o C x 50 o C
29
temperature added energy -20 o C 0 o C 50 o C = 10g x 2.1 J/g o C x 20 o C H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? use the following values: C ice = 2.1 J/g o c, H fus H 2 O = 6.01 kJ/mol, C H 2 O liq = 4.186 J/g o C total H = + H 2 + 5853 J = 420 J + 3340 J + 2093 J = 10g x 4.186 J/g o C x 50 o C
30
temperature added energy -20 o C 0 o C 50 o C = 10g x 2.1 J/g o C x 20 o C H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? It takes 5853 joules to heat up 10 grams of water from -20 o C to +50 o C. = 10g x 4.186 J/g o C x 50 o C
31
temperature added energy -20 o C 0 o C 50 o C = 10g x 2.1 J/g o C x 20 o C H 2 =10 g x 1mol/18g x 6.01 kJ/mol EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? It takes 5853 joules to heat up 10 grams of water from -20 o C to +50 o C. = 10g x 4.186 J/g o C x 50 o C
32
temperature added energy -20 o C 0 o C 50 o C EXAMPLE : What is H for 10 g water with a total t from -20 o C to +50 o C? It takes 5853 joules to heat up 10 grams of water from -20 o C to +50 o C. 5853 J
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.