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Published byFelicia Lindsey Modified over 8 years ago
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6 Measuring length and distance Foundation exercise P.55 1.The distance between the two places on the map is : 6.7 cm (Linear distance) The map scale is : 1 : 20 000 1 cm to 200 m ∴ The distance on the ground is : 200 m 6.7 = 1 340 m (1.34 km)
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2.The length of Deep Bay Road on the map is 5 cm. The map scale is : 1 : 20 000 1 cm to 200 m ∴ The length of Deep Bay Road on the ground is : 200 m 5 = 1 000 m 3. a)The length of the river on the map is 11.5 cm. The map scale is : 1 : 20 000 1 cm to 200 m ∴ The length of the river on the ground is : 200 m 11.5 = 2 300 m b)The distance on the map is : 10.8 cm (Linear distance) The map scale is : 1 : 20 000 1 cm to 200 m ∴ The distance on the ground is : 200 m 10.8 = 2 160 m c)With reference to 2b), the length of the river is 2 300 m. ∴ The number of hours need to complete the journey is : 2 300 m 5m = 460 minutes = 7.67 hours (i.e. 460 minutes 60 minutes)
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4.The longest section of the park on the map is 4.2 cm. (Refer to right diagram.) The map scale is : 1 : 20 000 1 cm to 200 m ∴ The longest section of the park is : 200 m 4.2 = 840 m 5. a)The length of the light transit railway on the map is 5.5 cm The map scale is : 1 : 20 000 1 cm to 200 m ∴ The length of the light transit railway on the ground is : 200 m 5.5 = 1 100 m b)With reference to 5a), the length of the railway is 1 100 m. ∴ The time needed to complete the journey is : 1 100 m 60 km = 1 100 m 60 000 m = 0.0183 hour = 1.1 minutes (i.e. 60 minutes 0.0183)
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