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Published bySara Franklin Modified over 9 years ago
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Standard Deviation
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Standard Deviation as a “Ruler” How can you compare measures – be it scores, athletic performance, etc., across widely different groups? Book Example: Who wins a heptathlon? The trick to comparing very different looking values is to use the standard deviation You are asking, in a sense, how far is a given value from the mean?
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A Quick Example Long JumpShot Put Mean6.16m13.29m SD.23m1.24m n2628 Kluft6.78m14.77m Skujyte6.30m16.4m Kluft’s 6.78m long jump is 0.62m longer than the mean jump of 6.16m The SD for the event was 0.23m, so her jump was (6.78-6.16)/0.23 = 2.70 standard deviations better than the mean
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A Quick Example (Cont.) Long JumpShot Put Mean6.16m13.29m SD.23m1.24m n2628 Kluft6.78m14.77m Skujyte6.30m16.4m Skujyte’s winning shot put was 16.4-13.29 = 3.11 meters longer than the mean shot put distance. That is 3.11/1.24=2.51 standard deviations better than the mean
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A Quick Example (Cont.) Long JumpShot Put Mean6.16m13.29m SD.23m1.24m n2628 Kluft6.78m14.77m Skujyte6.30m16.4m Kluft’s long jump was 2.70 standard deviations better than the mean Skujyte’s shot put was 2.51 standard deviations better than the mean. Who had the more impressive performance?
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Standardizing with z-Scores Expressing distance in standard deviations standardizes performances. To standardize a value we subtract the mean performance from the individual performance then divide by the standard deviation
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z-Scores A z-Score of 2 tells us that a data value is 2 standard deviations above the mean. A z-Score of -1.6 tells us the data value was 1.6 standard deviations below the mean The farther a data value from the mean the more impressive it is, regardless of sign. Kluft’s long jump with z- score 2.7 is more impressive than Skujyte’s shot put with z-score 2.51
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Just Checking (pg 107)
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The lower of your two tests will be dropped. You got a 90 on test 1, an 80 on test 2 You are all set to drop the 80… BUT WAIT! Your teacher announces she grades “on a curve.” She standardizes the scores in order to decide the lower one. The mean of the first test was 88 with sd=4, the mean on the second was 75 with sd=5 a)Which one will be dropped? b)Does this seem “fair” ?
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On first test, mean = 88, sd = 4 z= (90-88)/4 =.5 On second test, mean=75, sd=5 z=(80-75)/5 = 1.0 The first test has a lower z-score so it will be the one that gets dropped No, this doesn’t seem fair. The second test is 1 sd above the mean, farther away than the first, so it’s the better score relative to the class.
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Shifting Data When we standardize data to get z-scores we do two things: We shift the data by subtracting the mean We rescale the values by dividing by their standard deviation What happens to a grade distribution if everyone gets 5 extra points? If we switch feet to meters, what happens to the distribution of the heights of students?
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Shifting When we shift the data by adding (or subtracting) a constant to each value all measures of position (center, percentiles, min, max) will increase (or decrease) by the same constant Spread is not affected. Shape doesn’t change, spread doesn’t change: Not range, not IQR, not the SD
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Rescaling Converting from something like kilograms to pounds is an act of rescaling the data: To move from kg to lbs we multiply kg*2.2lbs/kg This will not change the shape of the distribution Mean gets multiplied by 2.2 In fact, all measures of position are multiplied by the same constant
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Rescaling What do you think happens to spread? The spread of pounds would be larger than the spread of kg after rescaling. By how much? 2.2 times larger!
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Rescaling When we multiply or divide all the data values by a constant all measures of position (mean, median, percentiles) are multiplied or divided by that same constant. The same is true for measures of spread: all measures of spread are multiplied or divided by that same constant
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Just Checking (pg 110) Before re-centering some SAT scores, the mean of all test scores was 450 - How would adding 50pts to each score affect the mean? - The SD = 100pts, what would it be after adding 50 pts?
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- Mean would increase to 500 - SD is still 100 pts
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Back to z-Scores Standardizing into z- Scores: Shift them by the mean Rescale by the Standard Deviation When we divide by s, the standard deviation gets divided by s as well The new SD becomes 1
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Z-Scores have a mean of 0 and a standard deviation of 1 Standardizing into z-Scores does not change the shape of the distribution of a variable Standardizing into z-Scores changes the center by making it 0 Standardizing into z-Scores changes the spread by making the SD = 1 Z-Scores
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When is a z-score BIG? As a rule, z-scores are big at around 3, definitely big around 6 or 7… But that isn’t nearly enough!
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Homework 129, # 1, 2, 3, 5, 7, 9, 24 Page 130, # 26, 29, 30, 34, 43 (Previously Assigned)
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