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Published byKatrina Veronica Porter Modified over 9 years ago
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Construcción de cladogramas y Reconstrucción Filogenética
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DATOS: Alineamiento de secuencias de genes
Cómo podemos transformar esta información a un contexto histórico?
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Patrón de Electroforesis en Campo Pulsado
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Spoligotyping de aislados clínicos de M. tuberculosis
Cepas 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43
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Dendograma y patrones RFLP de aislados clínicos de M. tuberculosis
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Las bandas polimórficas son convertidas en arreglos de 0 y 1 (0=ausencia de banda, 1=presencia de banda) H37Rv CDC H37Ra H37Pe
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Phylogeny inference Distance based methods -Pair wise distance matrix
-Adjust tree branch lengths to fit the distance matrix (ex. Minimum squares, Neighbor joining) 2. Character based methods -Parsimony -Maximum likelihood or model based evolution
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In 1866, Ernst Haeckel coined the word “phylogeny” and presented phylogenetic trees for most known groups of living organisms.
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Surf the tree of life at:
The Tree of Life project Surf the tree of life at:
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What is a tree? A tree is a mathematical structure which is used to model the actual evolutionary history of a group of sequences or organisms, i.e. an evolutionary hypothesis. A tree consists of nodes connected by branches. The ancestor of all the sequences is the root of the tree Internal nodes represent hypothetical ancestors Terminal nodes represent sequences or organisms for which we have data. Each is typically called a “Operational Taxonomical Unit” or OTU.
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Types of Trees Bifurcating Multifurcating Polytomy
Polytomies: Soft vs. Hard Soft: designate a lack of information about the order of divergence. Hard: the hypothesis that multiple divergences occurred simultaneously
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Types of Trees Trees Networks Only one path between any pair of nodes
More than one path between any pair of nodes
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Comments on Trees Trees give insights into underlying data
Identical trees can appear differently depending upon the method of display Information maybe lost when creating the tree. The tree is not the underlying data.
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Given a multiple alignment, how do we construct the tree?
A - GCTTGTCCGTTACGAT B – ACTTGTCTGTTACGAT C – ACTTGTCCGAAACGAT D - ACTTGACCGTTTCCTT E – AGATGACCGTTTCGAT F - ACTACACCCTTATGAG ?
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Construction of a distance tree using clustering with the Unweighted Pair Group Method with Arithmatic Mean (UPGMA) First, construct a distance matrix: A - GCTTGTCCGTTACGAT B – ACTTGTCTGTTACGAT C – ACTTGTCCGAAACGAT D - ACTTGACCGTTTCCTT E – AGATGACCGTTTCGAT F - ACTACACCCTTATGAG A B C D E 2 4 6 F 8 From
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UPGMA First round A B C D E 2 4 6 F 8 dist(A,B),C = (distAC + distBC) / 2 = 4 dist(A,B),D = (distAD + distBD) / 2 = 6 dist(A,B),E = (distAE + distBE) / 2 = 6 dist(A,B),F = (distAF + distBF) / 2 = 8 A,B C D E 4 6 F 8 Choose the most similar pair, cluster them together and calculate the new distance matrix.
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UPGMA Second round A,B C D E 4 6 F 8 Third round A,B C D,E 4 6 F 8
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UPGMA AB,C D,E 6 F 8 ABC,DE F 8 Fourth round Fifth round
6 F 8 Fifth round ABC,DE F 8 Note the this method identifies the root of the tree.
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UPGMA assumes a molecular clock
The UPGMA clustering method is very sensitive to unequal evolutionary rates (assumes that the evolutionary rate is the same for all branches). Clustering works only if the data are ultrametric Ultrametric distances are defined by the satisfaction of the 'three-point condition'. The three-point condition: A B C For any three taxa, the two greatest distances are equal.
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(Neighbor joining will get the right tree in this case.)
UPGMA fails when rates of evolution are not constant A tree in which the evolutionary rates are not equal A B C D E 5 4 7 10 6 9 F 8 11 (Neighbor joining will get the right tree in this case.) From
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Character state methods
MAXIMUM PARSIMONY Logic: Examine each column in the multiple alignment of the sequences. Examine all possible trees and choose among them according to some optimality criteria Method we’ll talk about Maximum parsimony
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Maximum Parsimony Simpler hypotheses are preferable to more complicated ones and that as hoc hypotheses should be avoided whenever possible (Occam’s Razor). Thus, find the tree that requires the smallest number of evolutionary changes. W - ACTTGACCCTTACGAT X – AGCTGGCCCTGATTAC Y – AGTTGACCATTACGAT Z - AGCTGGTCCTGATGAC W X Y Z
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Maximum Parsimony Start by classifying the sites:
Mouse CTTCGTTGGATCAGTTTGATA Rat CCTCGTTGGATCATTTTGATA Dog CTGCTTTGGATCAGTTTGAAC Human CCGCCTTGGATCAGTTTGAAC Invariant * * ******** ***** Variant ** * * ** Informative ** ** Non-inform. * *
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Mouse CTTCGTTGGATCAGTTTGATA Rat CCTCGTTGGATCATTTTGATA
Mouse CTTCGTTGGATCAGTTTGATA Rat CCTCGTTGGATCATTTTGATA Dog CTGCTTTGGATCAGTTTGAAC Human CCGCCTTGGATCAGTTTGAAC ** * Mouse Rat Dog Human G G T T T G G G G G G G Site 5: G C G C T C Mouse Rat Dog Human T T T C C T C C T C T C Site 2: C C C C T C Mouse Rat Dog Human T T G G G G G T T G G T Site 3: T G T G G G
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Maximum Parsimony Mouse CTTCGTTGGATCAGTTTGATA Rat CCTCGTTGGATCATTTTGATA Dog CTGCTTTGGATCAGTTTGAAC Human CCGCCTTGGATCAGTTTGAAC Informative ** ** Mouse Rat Dog Human 3 1
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EVOLUCIÓN IN VITRO POR INTERMEDIO DE PCR
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