1. Lesson 6-7 Pages 298-302 Using Percent Equations Lesson Check 6-6

2. What you will learn! 1. How to solve percent problems using percent equations. 2. How to solve real-life problems involving discount and interest.

3. Percent equation Discount Simple interest

4. What you really need to know! In a percent equation, the percent is written as a decimal.

5. What you really need to know! % of BASE = PART The word “ of ” means multiply!

6. What you really need to know! The number after the word “of” is the base! The number near the word “is” is the part!

8. Example 1: Find 38% of 22. % x BASE = PART 38% x 22 = PART 0.38 x 22 = PART 8.36 = PART

9. Example 2: 19 is what percent of 25? % x BASE = PART % x 25 = 19 % = 19 ÷ 25 % = 0.76 76%

10. Example 3: 84 is 16% of what number? % x BASE = PART 16% x BASE = 84 0.16 x BASE = 84 BASE = 84 ÷ 0.16BASE = 525

11. Example 4: The regular price of a ring is $495. It is on sale at a 20% discount. What is the sale price of the ring? 20% x $495 = $99 $495 - $99 = $396

12. Example 5: Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495? I = prt

13. I is interest p is principal r is annual interest rate t is time in years

14. Example 5: Suppose you invest $2,000 at an annual interest rate of 4.5%. How long will it take to earn $495? 495 = 2,000 0.045 t 5.5 years = t

15. Page 300 Guided Practice #’s 4-11

17. Pages 298-300 with someone at home and study examples! Read:

18. Homework: Pages 301-302 #’s 12-40 even #’s 44-61 Lesson Check 6-7

23. Page 738 Lesson 6-7

24. Lesson Check 6-7