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MATH:7450 (22M:305) Topics in Topology: Scientific and Engineering Applications of Algebraic Topology Sept 9, 2013: Create your own homology. Fall 2013 course offered through the University of Iowa Division of Continuing Education Isabel K. Darcy, Department of Mathematics Applied Mathematical and Computational Sciences, University of Iowa http://www.math.uiowa.edu/~idarcy/AppliedTopology.html
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Homology 3 ingredients: 1.) Objects 2.) Grading 3.) Boundary map
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 2-simplex = triangle = {v 1, v 2, v 3 } 1-simplex = edge = {v 1, v 2 } e v1v1 v2v2 0-simplex = vertex = v Building blocks for a simplicial complex
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 2-simplex = triangle 1-simplex = edge e v1v1 v2v2 0-simplex = vertex = v Building blocks for a simplicial complex
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2-simplex = triangle = {v 1, v 2, v 3 } 1-simplex = edge = {v 1, v 2 } 0-simplex = vertex = v Building blocks for a simplicial complex
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Objects = generators Generators = X = { x | in A } Let R be a ring (or field) R[X] = { n 1 x 1 + n 2 x 2 + … + n k x k : x i in R } Ex: Z 2 [X] = { n 1 x 1 + n 2 x 2 + … + n k x k : x i in Z 2 }
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A free vector space over the field F generated by the elements x 1, x 2, …, x k consists of all elements of the form n 1 x 1 + n 2 x 2 + … + n k x k where n i in F. Examples of a field: R = set of real numbers Q = set of rational numbers Z 2 = {0, 1} Addition: (n 1 x 1 + n 2 x 2 + … + n k x k ) + (m 1 x 1 + m 2 x 2 + … + m k x k ) = (n 1 + m 1 ) x 1 + (n 2 + m 2 )x 2 + … + (n k + m k )x k Slide from preparatory lecture 4: Addition (and free vector spaces)
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A free vector space over the field F generated by the elements x 1, x 2, …, x k consists of all elements of the form n 1 x 1 + n 2 x 2 + … + n k x k where n i in F. Examples of a field: R = set of real numbers: πx + √2 y + 3z is in R[x, y, z] Q = set of rational numbers (i.e. fractions): (½)x + 4y is in Q[x, y] Z 2 = {0, 1}: 0x + 1y + 1w + 0z is in Z 2 [x, y, z, w] Slide from preparatory lecture 4: Addition (and free vector spaces)
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A free abelian group generated by the elements x 1, x 2, …, x k consists of all elements of the form n 1 x 1 + n 2 x 2 + … + n k x k where n i are integers. Example: Z[ x, x ] 4 ix + 2 I x – 2 i -3 x k + n iii Z = The set of integers = { …, -2, -1, 0, 1, 2, …}
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Grading Grading: Each object is assigned a unique grade Grading = Partition of R[x] Ex: Grade = dimension v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 Grade 2: 2-simplex = triangle = {v 1, v 2, v 3 } Grade 1: 1-simplex = edge = {v 1, v 2 } e v1v1 v2v2 Grade 0: 0-simplex = vertex = v
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Grading Grading: Each object is assigned a unique grade Grading = Partition of R[x] Ex: Grade: Cardinality Grade 2: 2-simplex = triangle = {v 1, v 2, v 3 } Grade 3: 3-simplex = tetrahedron = {v 1, v 2, v 3, v 4 } Grade 1: 1-simplex = edge = {v 1, v 2 } Grade 0: 0-simplex = vertex = {v}
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Grading Grading: Each object is assigned a unique grade. Grading = Partition of R[x]. Let X n = {x 1, …, x k } = generators of grade n. C n = set of n-chains = R[X n ]
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Boundary Map n : C n C n-1 such that 2 = 0 v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 e v1v1 v2v2 0 v1v1 v2v2 v2v2 e2e2 e1e1 e3e3 v1v1 v3v3
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{v 1, v 2 } {v 1 } + {v 2 } 0 {v 1, v 2, v 3 } {v 1, v 2 } + {v 1, v 3 } + {v 2, v 3 } Boundary Map n : C n C n-1 such that 2 = 0
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C n+1 C n C n-1 ... C 2 C 1 C 0 0 H n = Z n /B n = (kernel of )/ (image of ) null space of M n column space of M n+1 Rank H n = Rank Z n – Rank B n = n+1 n n210
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Your name homology 3 ingredients: 1.) Objects 2.) Grading 3.) Boundary map
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 2-simplex = face = {v 1, v 2, v 3 } Note that the boundary of this face is the cycle e 1 + e 2 + e 3 = {v 1, v 2 } + {v 2, v 3 } + {v 1, v 3 } 1-simplex = edge = {v 1, v 2 } Note that the boundary of this edge is v 2 + v 1 e v1v1 v2v2 0-simplex = vertex = v Unoriented simplicial complex using Z 2 coefficients Grading = dimension
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 2-simplex = oriented face = (v 1, v 2, v 3 ) 1-simplex = oriented edge = (v 1, v 2 ) Note that the boundary of this edge is v 2 – v 1 e v1v1 v2v2 0-simplex = vertex = v Note that the boundary of this face is the cycle e 1 + e 2 + e 3 = (v 1, v 2 ) + (v 2, v 3 ) – (v 1, v 3 ) = (v 1, v 2 ) – (v 1, v 3 ) + (v 2, v 3 ) Oriented simplicial complex Grading = dimension
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Cell complex Building block: n-cells = { x in R n : || x || ≤ 1 } 2-cell = open disk = { x in R 2 : ||x || < 1 } Examples: 0-cell = { x in R 0 : ||x || < 1 } 1-cell =open interval ={ x in R : ||x || < 1 } ( ) Grading = dimension (n-cells) = { x in R n : || x || = 1 } n
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Čech homology Given U V where V open for all in A. Objects = finite intersections = { V i in A } Grading = n = depth of intersection. ( V V Ex: (V V V V V V V V V V V V V V U i = 1 n i in A n+1 j = 1 n i i U i = 1 i ≠ j n U i = 1 n ( ) 0 1 U UUUUU 2
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Creating the Čech simplicial complex
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Consider X an arbitrary topological space. Let V = {V i | i = 1, …, n } where V i X, The nerve of V = N(V) where The k -simplices of N(V) = nonempty intersections of k +1 distinct elements of V. For example, Vertices = elements of V Edges = pairs in V which intersect nontrivially. Triangle = triples in V which intersect nontrivially. http://www.math.upenn.edu/~ghrist/EAT/EATchapter2.pdf
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Nerve Lemma: If V is a finite collection of subsets of X with all non-empty intersections of subcollections of V contractible, then N(V) is homotopic to the union of elements of V. http://www.math.upenn.edu/~ghrist/EAT/EATchapter2.pdf
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Creating the Vietoris Rips simplicial complex
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Betti numbers provide a signature of the underlying topology. Singh G et al. J Vis 2008;8:11 ©2008 by Association for Research in Vision and Ophthalmology
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From: http://www.math.cornell.edu/~mec/Winter2009/Victor/part1.htm
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From: http://plus.maths.org/content/imaging-maths-inside-klein-bottle From: http://www.math.osu.edu/~fiedorowicz.1/math655/Klein2.html Klein Bottle
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Betti numbers provide a signature of the underlying topology. Singh G et al. J Vis 2008;8:11 ©2008 by Association for Research in Vision and Ophthalmology
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http://www.journalofvision.org/ content/8/8/11.full Figure 4 animation
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Topology and Data. Gunnar Carlsson www.ams.org/journals/bull/2009-46-02/S0273-0979-09-01249-X
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 v6v6 v4v4 v5v5 e4e4 e6e6 e5e5
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 v6v6 v4v4 v5v5 e4e4 e6e6 e5e5
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 v6v6 v4v4 v5v5 e4e4 e6e6 e5e5 Z 1 = kernel of = null space of M 1 = o1o1
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v2v2 e2e2 e1e1 e3e3 v1v1 v3v3 v6v6 v4v4 v5v5 e4e4 e6e6 e5e5
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C 2 C 1 C 0 o1o1 o2o2 H 1 = Z 1 /B 1 = (kernel of )/ (image of ) null space of M 1 column space of M 2 Rank H 1 = Rank Z 1 – Rank B 1 = 2 – 1 = 1 o1o1 o2o2 = = v6v6 v4v4 v5v5 e3e3 e5e5 e4e4 v3v3 v1v1 v2v2 e1e1 e3e3 e2e2
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