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Students will….. Write chemical reactions using words and chemical symbols. Balance chemical equations using lowest whole number ratios. Identify, complete and balance combination rxns, decomposition rxns, combustion rxns, single-replacement rxns, and double-replacement rxns. Use the activity series of metals to determine whether or not a single replacement reaction will occur. Determine what element is oxidized and what element is reduced in a single replacement reaction. Use solubility rules to determine the products of double-replacement reactions. Write net ionic equations for aqueous reactions.
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Students will….. Write chemical reactions using words and chemical reactions. Balance chemical equations using lowest whole number ratio. Assignments to be Completed: ChemQuest 29 (Balancing Equations) Balancing Equations WS #1 Writing and Balancing WS #2 Textbook pp. 203-211 #1-10
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Chemical Equations A chemical equation uses formulas to express the identities and quantities of substances involved in a physical or chemical change. The formation of HF gas on the macroscopic and molecular levels.
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A three-level view of the reaction between magnesium and oxygen.
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Features of Chemical Equations Mg + O 2 MgO Reactants are written on the left. A yield arrow points from reactants to products. Products are written on the right. The equation must be balanced; the same number and type of each atom must appear on both sides.
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translate the statement balance the atoms using coefficients; formulas cannot be changed Start with metals, followed by nonmetals. If there is a polyatomic ion, keep it together. Once a coefficient has been placed in front of a chemical formula, make changes to the other side of the equation to balance what was changed by the coefficient. If doing a combustion reaction, the order should be carbon, hydrogen, oxygen. specify states of matter adjust coefficients if necessary check that all atoms balance Balancing a Chemical Equation magnesium and oxygen gas react to give magnesium oxide: Mg + O 2 → MgO 2Mg + O 2 → 2MgO 2Mg (s) + O 2 (g) → 2MgO (s)
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Aluminum foil is heated in the presence of oxygen gas to produce solid aluminum oxide. Silver nitrate solution is added to a solution of potassium phosphate to produce silver phosphate precipitate and aqueous potassium nitrate. Iron is added to hydrochloric acid to produce aqueous iron(III) chloride and hydrogen gas. Propane gas is burned in the presence of oxygen gas to produce carbon dioxide gas and gaseous water.
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translate the statement Sample Problem Balancing Chemical Equations PROBLEM: PLAN:SOLUTION: balance the atoms specify states of matter Within the cylinders of a car’s engine, the hydrocarbon octane (C 8 H 18 ), one of many components of gasoline, mixes with oxygen from the air and burns to form carbon dioxide and water vapor. Write a balanced equation for this reaction. adjust the coefficients check the atoms balance C 8 H 18 + O 2 CO 2 + H 2 O 2C 8 H 18 + 25O 2 16CO 2 + 18H 2 O 2C 8 H 18 (l) + 25O 2 (g) 16CO 2 (g) + 18H 2 O (g) C 8 H 18 + O 2 8 CO 2 + 9 H 2 O 25 2
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Molecular Scene Combustion of Octane
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Sample Problem Balancing an Equation from a Molecular Scene PROBLEM:The following molecular scenes depict an important reaction in nitrogen chemistry. The blue spheres represent nitrogen while the red spheres represent oxygen. Write a balanced equation for this reaction. PLAN:Determine the formulas of the reactants and products from their composition. Arrange this information in the correct equation format and balance correctly, including the states of matter.
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SOLUTION: The reactant circle shows only one type of molecule, composed of 2 N and 5 O atoms. The formula is thus N 2 O 5. There are 4 N 2 O 5 molecules depicted. The product circle shows two types of molecule; one has 1 N and 2 O atoms while the other has 2 O atoms. The products are NO 2 and O 2. There are 8 NO 2 molecules and 2 O 2 molecules shown. Sample Problem The reaction depicted is 4 N 2 O 5 → 8 NO 2 + 2 O 2. Writing the equation with the smallest whole-number coefficients and states of matter included; 2 N 2 O 5 (g) → 4 NO 2 (g) + O 2 (g)
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