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Extra Practice 2.5 COMPOUND INEQUALITIES Use lined paper or continue Cornell notes 22 < −3c + 4 < 14 − 4 − 4 − 4 18 < −3c < 10 ____ ____ ____ - 3 -3 -3.

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Presentation on theme: "Extra Practice 2.5 COMPOUND INEQUALITIES Use lined paper or continue Cornell notes 22 < −3c + 4 < 14 − 4 − 4 − 4 18 < −3c < 10 ____ ____ ____ - 3 -3 -3."— Presentation transcript:

1 Extra Practice 2.5 COMPOUND INEQUALITIES Use lined paper or continue Cornell notes 22 < −3c + 4 < 14 − 4 − 4 − 4 18 < −3c < 10 ____ ____ ____ - 3 -3 -3 Because there are no numbers that are both greater than −3 1 —3 and less than −6, the inequality has no solution. Note that the original inequality states that 22 < 14, so there is no solution

2 2m − 1 ≥ 5 or 5m > −25 Solve each separately m ≥ 3 or m > −5 Because all numbers greater than or equal to 3 are also greater than −5, every number greater than −5 makes at least one of the inequalities true. So, the solution of the compound inequality is m > −5.

3 −y + 3 ≤ 8 and y + 2 > 9 y ≥ −5 and y > 7 All numbers greater than 7 are also greater than −5, and make both inequalities true. So, the solution of the compound inequality is y > 7.

4 x − 8 ≤ 4 or 2x + 3 > 9 x ≤ 12 or x > 3 The graphs of these two inequalities overlap to cover the whole number line. So, all real numbers are a solution of one inequality or the other, and therefore all real numbers are a solution of the compound inequality.


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