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Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Chapter 1 Real Numbers and Introduction to Algebra
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22 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Bellwork: Quiz on Sections 1.2 and 1.3
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Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. 1.5 Subtracting Real Numbers
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44 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Objectives: Subtract real numbers Solve problems with subtraction Evaluate algebraic expressions Find complementary and supplementary angles
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55 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. If a and b are real numbers, then a – b = a + (– b) Subtracting Real Numbers
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66 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 1 Subtract. a. 4 ‒ 7 = ‒ 3 b. ‒ 8 ‒ ( ‒ 9) = 1 c. (–5) – 6 – (–3) = ‒ 8
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77 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 1 Subtract. a. 4 ‒ 7 = ‒ 3 b. ‒ 8 ‒ ( ‒ 9) = 1 c. (–5) – 6 – (–3) = ‒ 8
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88 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 1 Subtract. a. 4 ‒ 7 = ‒ 3 b. ‒ 8 ‒ ( ‒ 9) = 1 c. (–5) – 6 – (–3) = ‒ 8
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99 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Example 1 Subtract. a. 4 ‒ 7 = ‒ 3 b. ‒ 8 ‒ ( ‒ 9) = 1 c. (–5) – 6 – (–3) = ‒ 8
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10 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Subtract. a. 6.9 ‒ ( ‒ 1.8) = 6.9 + 1.8 = 8.7 b. Example 2
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11 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Subtract. a. 6.9 ‒ ( ‒ 1.8) = 6.9 + 1.8 = 8.7 b. Example 2
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12 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Subtract. a. 6.9 ‒ ( ‒ 1.8) = 6.9 + 1.8 = 8.7 b. Example 2
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13 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Subtract. a. 6.9 ‒ ( ‒ 1.8) = 6.9 + 1.8 = 8.7 b. Example 2
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14 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Subtract. a. 6.9 ‒ ( ‒ 1.8) = 6.9 + 1.8 = 8.7 b. Example 2
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15 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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16 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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17 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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18 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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19 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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20 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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21 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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22 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Simplify each expression. a. ‒ 9 – 5 + 11 – ( ‒ 7) = ‒ 9 + (–5) + 11 + 7 = 4 b. Example 3
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23 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4
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24 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in!
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25 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in!
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26 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in!
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27 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in!
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28 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in! Simplify.
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29 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in! Simplify.
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30 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in! Simplify.
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31 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Find the value of the expression when x = 4 and y = ‒ 3. Example 4 Plug it in! Simplify.
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32 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15.
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33 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15.
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34 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15. Plug it in!
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35 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15. Plug it in!
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36 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15. Plug it in!
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37 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15. Plug it in! Simplify.
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38 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15. Plug it in! Simplify.
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39 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Determine whether ‒ 6 is a solution of x – 9 = 15. Example 5 x – 9 = 15 ‒ 6 – 9 ? 15 –15 ≠ 15 Thus, ‒ 6 is not a solution of x – 9 = 15. Plug it in! Simplify.
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40 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6
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41 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for?
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42 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for?
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43 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for? What do we need to find it?
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44 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for? What do we need to find it?
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45 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for? What do we need to find it?
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46 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for? What do we need to find it? For the overall change, we take the end temp and subtract the beginning temp.
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47 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for? What do we need to find it? For the overall change, we take the end temp and subtract the beginning temp. -23° - 14°
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48 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for? What do we need to find it? For the overall change, we take the end temp and subtract the beginning temp. -23° - 14° = -37°
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49 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. At 6:00 PM, the temperature at the Winter Olympics was 14°; by morning the temperature dropped to -23°. Find the overall change in temperature. Example 6 What are we looking for? What do we need to find it? For the overall change, we take the end temp and subtract the beginning temp. -23° - 14° = -37°
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50 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Complementary angles are two angles whose sum is 90 o. Find the measure of the following complementary angles. x 37° Complementary Angles Example:
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51 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Complementary angles are two angles whose sum is 90 o. Find the measure of the following complementary angles. x 37° Complementary Angles Example:
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52 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Complementary angles are two angles whose sum is 90 o. Find the measure of the following complementary angles. x 37° Complementary Angles Example:
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53 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Complementary angles are two angles whose sum is 90 o. Find the measure of the following complementary angles. x 37° Complementary Angles Example:
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54 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Complementary angles are two angles whose sum is 90 o. Find the measure of the following complementary angles. x 37° Complementary Angles Example:
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55 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Complementary angles are two angles whose sum is 90 o. Find the measure of the following complementary angles. x 37° Complementary Angles Example:
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56 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Supplementary angles are two angles whose sum is 180 o. Find the measure of the following supplementary angles. x123° Supplementary Angles Example:
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57 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Supplementary angles are two angles whose sum is 180 o. Find the measure of the following supplementary angles. x123° Supplementary Angles Example:
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58 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Supplementary angles are two angles whose sum is 180 o. Find the measure of the following supplementary angles. x123° Supplementary Angles Example:
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59 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Supplementary angles are two angles whose sum is 180 o. Find the measure of the following supplementary angles. x123° Supplementary Angles Example:
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60 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Supplementary angles are two angles whose sum is 180 o. Find the measure of the following supplementary angles. x123° Supplementary Angles Example:
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61 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Supplementary angles are two angles whose sum is 180 o. Find the measure of the following supplementary angles. x123° Supplementary Angles Example:
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62 Copyright © 2012 Pearson Education, Inc. Publishing as Prentice Hall. Closure: Verbally review objectives with students.
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