1. Water Resources Planning and Management Daene C. McKinney Economic Analysis of Alternative Water Plans: 1. Benefit/Cost Analysis

2. Water Resources Development Need for water is becoming more acute Governments & investors –Develop water resources –Expenditures are large Choices among alternative should –Be efficient –Meet needs of stakeholders –Spend money wisely O. Eckstein, Water Resources Development, Harvard University Press, 1958

3. Benefit – Cost Analysis Goals –Ensure that projects use resources efficiently –Provide a framework for comparing alternative plans/projects –Estimate the impacts of regulatory changes Basic principle –Project benefits must exceed costs

4. Comparing Time Streams of Benefits and Costs Alternative plans have different time streams of net benefits B p (t) = benefits – costs Plan p is characterized by the time stream of net benefits it generates over its planning horizon T p {B 1 p, B 2 p, B 3 p,..., B Tp p } If benefits exceed costs, B t p > 0 Time Benefits OM&R costs Initial cost Costs t

5. Benefits and Costs Express in similar units (e.g., $) Compare for each alternative Viewpoint is important –Some groups will view some things as benefits, others as costs; other groups may differ. Compare differences between alternatives Do not consider effects not attributable to alternatives Opportunity cost –Net benefits forgone in the choice of one expenditure over others

6. Costs of Alternatives Direct costs of each alternative –Capital costs Acquisition of land and materials, construction costs Opportunity costs (what you COULD have made…) –Operation, maintenance, and replacement costs Indirect costs of each alternative –Costs imposed on society or the environment Valuation techniques –Market value Capital costs and O&M costs Benefits from revenues from future deliveries of water –No market value? Then what? Value = cost of cheapest alternative Value can be estimated in other ways

7. Imagine you take $100 to the bank and put it into a savings account that has an “annual” rate of 5%. What would it be worth at the end of 1 year? Interest Rate Formulas

8. $P invested for T years at an annual interest rate of i% is worth $F T in the future: $F available T years in the future is worth $P today at an annual interest rate of i% Interest Rate Formulas

9. Uniform payments F t at the end of every year t for t=1,2,…,T years in the future is worth (in the present) Interest Rate Formulas P 0 T Time t at an annual interest rate of i% F1F1 F2F2 FtFt FTFT F T-1

10. Interest Rate Formulas P A P = present value F = Future payment A = annual series AAAAA … 0 T Time t

11. Home Mortgage Payments Monthly fixed-rate mortgage payments, M where L = total amount of the mortgage (Loan) i = monthly interest rate = annual percentage rate/12 n = number of months of the loan Example $250,000 30-year mortgage with 6.5% annual rate

12. Cash Flow Diagrams Time, t Benefits OM&R costs, OMC t Capital cost C 0 Benefits, B t Costs

13. Benefits OM&R costs, OMC t Time, t Benefits, B t Costs Cash Flow Diagrams PW B Capital cost C 0

14. Cash Flow Diagrams Benefits Time, t Costs PW B Annual Benefits, B t Total annual cost, C t T C0C0

15. Example: Pumping Plant AlternativeInitial costAnnual O&M cost Salvage value Life (yrs) A$525k$26k050 B$312k$48k$50k25 050 Time (yrs) 25 A B $525k (one time) $26k (every year) 050 Time (yrs) 25 A

16. 050 Time (yrs) 25 A B Example: Pumping Plant AlternativeInitial costAnnual O&M cost Salvage value Life (yrs) A$525k$26k050 B$312k$48k$50k25 $312k $50k $48k (every year) 050 Time (yrs) 25 B

17. Example : Pumping Plant $525k $312k $50k $26k $48k 050 Time (yrs) 25 A B Annual cost of alternative A

18. Example : Pumping Plant $525k $312k $50k $26k $48k 050 Time (yrs) 25 A B Annual cost of alternative B

19. Example : Pumping Plant $525k $312k $50k $26k $48k 050 Time (yrs) 25 A B Annual cost of each alternative

20. Discount Rate Time value of capital used when comparing alternatives US federal practice “Average rate of interest on government bonds with terms of 15 years or more” http://www.nrcs.usda.gov/wps/portal/nrcs/detail//?cid=nrcs143_009685

21. Incremental Benefit - Cost Method 1.For each alternative –Define consequences –Estimate value of consequences –Calculate B/C ratios, Discard any with B/C < 1 2.Order alternatives: Lowest to highest cost 3.Select lowest cost alternative as “Current Best” –Next higher cost alternative is “Contender” 4.Compare “Best” to “Contender” –Compute  B/  C, If  B/  C > 1, Contender becomes Best 5.Repeat Step 4 for all alternatives 6.Final “Current Best” is “Preferred Alternative”

22. Example Project with the highest benefit-cost ratio may not always be the preferred alternative. Consider a project with benefits of 3 units and costs of 1 unit Suppose you can invest another 4 units to increase benefits to 10 units. +4 But B/C A = 3!

23. Example Four projects identified for recreational facilities at a Lower Colorado River Authority facility Inspection of the benefit-cost ratios might lead one to select Alternative B because the ratio is a maximum This choice is not correct. Correct alternative selected by incremental benefit-cost method where the additional increment of investment is desirable if the incremental benefit realized exceeds the incremental outlay.

24. Example (Cont.) The alternatives must be arranged in order of increasing outlay. Thus, the alternative with the lowest initial cost should be first, the alternative with the next lowest initial cost second, and so forth.