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Circle of Life. Proteins Organic polymers made from amino acids Must be linked and folded in specific ways to function properly Coded into our DNA Enzymes,

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Presentation on theme: "Circle of Life. Proteins Organic polymers made from amino acids Must be linked and folded in specific ways to function properly Coded into our DNA Enzymes,"— Presentation transcript:

1 Circle of Life

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3 Proteins Organic polymers made from amino acids Must be linked and folded in specific ways to function properly Coded into our DNA Enzymes, hormones, and antibodies

4 20 Amino Acids Nonessential (14) –Body manufactures them naturally Essential (6) –Must obtain from the food we eat –Kwashiorkor = “rejected one” Protein deficiency which often occurs in children where protein is scarce Once child stops breastfeeding their diet becomes high in fiber and carbohydrates but lacking in protein. This causes liver to become enlarged and creates a swollen belly

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6 Blood Sugar amount of glucose in blood job is to provide energy Bad carbohydrates –Refined and processed –Easy for body to break down & absorb causing a spike (sugar high) Good carbohydrates –Difficult for body to break down sugars –Enters blood at a slower rate and does not produce sugar high –Fruits, veggies, greens, whole grains

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8 Lipids Fats Used to store energy If there is too much sugar in the blood, the body will convert sugar to fat and store it as triglycerides

9 Fats Unsaturated fats –Come from plants –Contain double bond –Easier to break down Saturated fats –Contains all single bonds –Difficult to break down and often stay in bloodstream blocking arteries

10 Anabolism –Uses energy to combine smaller molecules to make needed substances –Growth hormone –Insulin –Testosterone Catabolism –Break down of molecules –Usually to get energy –Digesting your food for example

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12 Tomorrow’s Lab Calorimeter- is an insulated device used to measure the amount of heat absorbed or released during a chemical process

13 Law of Conservation of Energy = energy (heat) can not be created nor destroyed Heat lost = heat gained Q metal = Q water C x m x ΔT = C x m x ΔT

14 Specific Heat Practice I Determine the specific heat of the metal: –Mass of the metal =183 g –Initial temp of metal =100°C –Mass of water=100 g –Initial temp or water = 9°C –Temp of water after metal =28°C Q lost = Q gained Q metal = Q water C m ΔT = C m ΔT C (183) (28-100) = 4.184 (100) (28-9) C (183) (-72) = 4.184 (100)(19) C (13176) = 7949.6 C = 0.603


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