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REVIEW HOMEWORK ?? What is the formula for Avogadro’s Law? What happens to volume when the number of moles increases? Avogadro’s Law Questions 1-4
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REVIEW HOMEWORK ?? What is the formula for Boyles Law? What happens to volume when pressure increases? Boyle’s Law Questions 1-8
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Charles’ Law Jacques Charles 1746 – 1823 1746 – 1823
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Charles’ Law At constant pressure, the volume of a gas varies directly with its Kelvin temperature Equation: V1 V2 = T1 T2 Volume = L Temperature = K
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Charles’ Law Cross multiply the equation: V2V2 = T1T1 T2T2 V1V1 Resulting Equation: V 1 T 2 = V 2 T 1
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At Constant Pressure, V T means proportional When volume, temp Temp. scale K not °C What error exists on this graph?
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Solving Charles’ Law Problems –Write the given information –Determine an equation to use –Isolate the missing variable –Convert to Kelvin temp. scale –Plug-in the given values and solve
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Write Given Info. A volume of 20.0m 3 of argon gas is kept under constant pressure. The gas is heated from 22ºC to 283 ºC. What is the new volume of the gas? V 1 = 20.0 m 3 T 1 = 22ºC T 2 = 283 º C V 2 = ?
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Determine an Equation & Isolate V 2 V 1 T 2 = V 2 T 1 T1T1 T1T1 V1T2V1T2 T1T1 = V 2
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Temperature Conversion Equations Celsius to Kelvin K = ºC + 273 Fahrenheit to Celsius ºC = 5/9 (º F – 32)
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Convert ºC to K Given Info. V 1 = 20.0 m 3 T 1 = 22ºC T 2 = 283 º C V 2 = ? K = ºC + 273 K = 22 + 273 K = 295 K = ºC + 273 K = 283 + 273 K = 556
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Plug-in Given Values and Solve Given Info. V 1 = 20.0 m 3 T 1 = 295K T 2 = 556K V 2 = ? V1T2V1T2 T1T1 = V 2 (20.0 m 3 )(556K) = V 2 295K 37.7 m 3 = V 2
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Turn to a person next to you… “I’m here to help whenever I can”
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Outstanding Teamwork! Let’s try a few more Charles’ Law problems.
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EXERCISE
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