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Unit 5 Part 1 Perpendicular Bisector, Median and Altitude of Triangles.

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Presentation on theme: "Unit 5 Part 1 Perpendicular Bisector, Median and Altitude of Triangles."— Presentation transcript:

1 Unit 5 Part 1 Perpendicular Bisector, Median and Altitude of Triangles

2 Midpoint of a segment

3 Perpendicular Bisector Any point on the perpendicular bisector of a line segment is equidistance from the endpoints of the segment.

4 Perpendicular Bisector of a Triangle. The perpendicular bisector of a triangle is formed by constructing perpendicular bisectors of each side of the triangle. GeoGebra File Perpendicular bisector Circumscribed circle

5 Median of a Triangle The median of a triangle is the line segment from a vertex to the midpoint of the opposite side of that vertex. GeoGebra File

6 Altitude of a Triangle Altitude also known as the height.

7 Angle Bisector Any point on the angle bisector is equidistance from the sides of the angle.

8 Solve for ‘x’. 3x – 10 2x + 18 3x – 10 = 2x +18 - 2x x – 10 = 18 +10 + 10 x = 28 x

9 Angle bisector of a triangle. GeoGebra File Angle bisector Inscribed circle

10 Draw AB is a median of ∆BOC RA is the altitude and median of ∆RST AE and CD are ∠ bisectors of ∆ACB and intersect at “x”. FS and AV are altitudes of ∆FAT and intersect outside the triangle.

11 S N E L R M SM is an _______________ of ∆RSE. If SN = NE, then RN is a _____________ of ∆RSE. If ∠SNL is congruent to ∠LER, then LE is an ____________________ of ∆RSE. SN = NE, therefore NT is a ___________________ of ∆RSE T Altitude Median Angle Bisector Perpendicular Bisector

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