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Published byLynne Williams Modified over 9 years ago
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Warm Up #13 1 (6x 3 + 12x 2 – 18x) 3x 2 (4x 2 + 9x +2) (x+2) 3 (x 3 + 216) (x + 6)
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Warm Up #13: 1 (6x 3 + 12x 2 – 18x) 3x 2 (4x 2 + 9x +2) (x+2) 3 (x 3 + 216) (x + 6) x 2 – 6x +36 4x + 1 2x 2 + 4x - 6
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Complex Rational Expressions Fractions inside of fractions are a NO - NO And must be simplified.
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To simplify Complex Rational Expressions Multiply the numerator and denominator by a fraction equivalent to “1” The fraction should contain the factors of all denominators in the expression
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Complex Rational Expressions Multiply the numerator and denominator by a fraction equivalent to “1” The fraction should contain the factors of all denominators in the expression
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Steps 1.Find the LCD of the numerator and denominator 2.Multiply the complex rational expression by the LCD/LCD (so its equivalent to multiplying by 1) 3.Simplify (factor and cross out common factors)
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Short Cut If there are 2 terms or more on either the numerator or denominator you must multiply by the LCD/LCD However, if there is only 1 term on the numerator and 1 term on the denominator then you can divide fractions (which means multiply by the reciprocal)
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Assignment: Page 470 2-27 odd
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