Presentation is loading. Please wait.

Presentation is loading. Please wait.

2003 Paul M. VanRaden Animal Improvement Programs Laboratory Agricultural Research Service, USDA, Beltsville, MD Comparison of Longevity.

Similar presentations


Presentation on theme: "2003 Paul M. VanRaden Animal Improvement Programs Laboratory Agricultural Research Service, USDA, Beltsville, MD Comparison of Longevity."— Presentation transcript:

1 2003 Paul M. VanRaden Animal Improvement Programs Laboratory Agricultural Research Service, USDA, Beltsville, MD paul@aipl.arsusda.gov Comparison of Longevity and Fertility Trait Definitions in Theory and Simulation

2 Interbull Workshop March 2-3, 2003 (2) P.M. VanRaden 2003 Goals  Compare methods to evaluate non- normally distributed traits Linear analysis of length of time Binomial analysis of culling rate Survival analysis for log(culling rate)  Try to understand parameters  Evaluate sires from simulated data

3 Interbull Workshop March 2-3, 2003 (3) P.M. VanRaden 2003 Current Longevity Evaluations  Linear animal or sire models Binomial culling rate – Single EBV = c (SWE, Cornell) – Multiple EBV = c t (CAN, AUS, IRL) Productive life – Single EBV = 1/c (USA, GBR, ISR) – Multiple EBV = 1/c t (NZL)  Non-linear sire-MGS models Survival analysis – Single EBV = log(c * env t ) (DEU, FRA, NLD, ITA, BEL, CHE)

4 Interbull Workshop March 2-3, 2003 (4) P.M. VanRaden 2003 Animal vs Sire-MGS Models  Value of maternal relatives Average of 5 maternal brothers for bulls proven in USA Extra info is worth 10-20 daughters when heritability is low (.10 to.03) Animal vs sire models differ more than linear vs non-linear (Boettcher et al 1999 JDS 82:1034)  All relatives or non-linear math?

5 Interbull Workshop March 2-3, 2003 (5) P.M. VanRaden 2003 Distribution of Longevity

6 Interbull Workshop March 2-3, 2003 (6) P.M. VanRaden 2003 ≤ 50 ≥ 250 Distribution of Days Open Holstein Calvings 1990 - 2001 Cows culled for reproductive reasons

7 Interbull Workshop March 2-3, 2003 (7) P.M. VanRaden 2003 Toss Coin Until Head Observed

8 Interbull Workshop March 2-3, 2003 (8) P.M. VanRaden 2003 Maximum Likelihood  Define fraction of cows culled in each lactation = c and number of lactations survived by cow i = y i Prob(y i | c) = c (1 – c) (Yi – 1) ML estimate of c = n / Σ y i Linear estimate of (1/c) = Σ y i / n  Culling rate is just reciprocal of number of lactations (no info lost)

9 Interbull Workshop March 2-3, 2003 (9) P.M. VanRaden 2003 Prior Distributions  Sire effects normal for: Number of lactations (linear model) Culling rate (binomial model) Log of culling rate (survival model)  Differences are small if heritability is low  Prob (y | c) can be the same, but Prob (c) differs

10 Interbull Workshop March 2-3, 2003 (10) P.M. VanRaden 2003 Comparison of Priors

11 Interbull Workshop March 2-3, 2003 (11) P.M. VanRaden 2003 Simulated Data  500 sires with 10-1000 daughters, 10 replicates  Sire effects normal for log (c /.33) BV for log(relative risk) transformed to culling rate and longevity by non-linear formulas True BV had product-moment (linear) correlations of.98 to.995.  What scale should MACE work on?

12 Interbull Workshop March 2-3, 2003 (12) P.M. VanRaden 2003 Simulation Results  Heritability estimates.106 for number of lactations.038 for culling rate (per lactation).091 for log(number of lactations)  True accuracy, or corr (EBV, BV).72 for number of lactations.72 for culling rate.70 for log(number of lactations)

13 Interbull Workshop March 2-3, 2003 (13) P.M. VanRaden 2003 Conclusions  Including all relatives is more important when heritability is low  EBV from repeated binomial models are reciprocals of PL  True reliabilities are similar, but reported reliabilities differ slightly  Linear functions of data seem OK


Download ppt "2003 Paul M. VanRaden Animal Improvement Programs Laboratory Agricultural Research Service, USDA, Beltsville, MD Comparison of Longevity."

Similar presentations


Ads by Google