2. Chapter 17 Energy in Thermal Processes: First Law of Thermodynamics

3. 2 Fig. 17-CO, p. 531

4. 3 17.1 Thermodynamics – Historical Background Thermodynamics and mechanics were considered to be separate branches Until about 1850 Experiments by James Joule and others showed a connection between them A connection was found between the transfer of energy by heat in thermal processes and the transfer of energy by work in mechanical processes The concept of energy was generalized to include internal energy The Law of Conservation of Energy emerged as a universal law of nature

5. 4 James Prescott Joule 1818 – 1889 Largely self-educated Work led to establishing Conservation of Energy Determined the mechanical equivalent of heat

6. 5 Internal Energy Internal energy is all the energy of a system that is associated with its microscopic components These components are its atoms and molecules The system is viewed from a reference frame at rest with respect to the system

7. 6 Internal Energy and Other Energies The kinetic energy due to its motion through space is not included Internal energy does include kinetic energies due to Random translational motion Rotational motion Vibrational motion Internal energy also includes intermolecular potential energy

8. 7 Heat Heat is a mechanism by which energy is transferred between a system and its environment due to a temperature difference between them The term heat will also be used to represent the amount of energy, Q, transferred by this mechanism

9. 8 Heat vs. Work Work done on or by a system is a measure of the amount of energy transferred between the system and its surroundings Heat is energy that has been transferred between a system and its surroundings due to a temperature difference

10. 9 Fig. 17-1, p. 532

11. 10 Units of Heat Historically, the calorie was the unit used for heat One calorie is the heat necessary to raise the temperature of 1 g of water from 14.5 o C to 15.5 o C The Calorie used for food is actually 1 kcal In the US Customary system, the unit is a BTU (British Thermal Unit) One BTU is the heat required to raise the temperature of 1 lb of water from 63 o F to 64 o F The standard in the text is to use Joules

12. 11 Mechanical Equivalent of Heat 1 cal = 4.186 J This is known as the mechanical equivalent of heat It is the current definition of a calorie The Joule as the SI unit of heat was adopted in 1948

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16. 15 17.2 Specific Heat Specific heat, c, is the heat amount of energy per unit mass required to change the temperature of a substance by 1°C If energy Q transfers to a sample of a substance of mass m and the temperature changes by  T, then the specific heat is

17. 16 Specific Heat, cont The specific heat is essentially a measure of how insensitive a substance is to the addition of energy The greater the substance’s specific heat, the more energy that must be added to cause a particular temperature change The equation is often written in terms of Q: Q = m c  T Units of specific heat are J/ k. °C

18. 17 Some Specific Heat Values

19. 18 More Specific Heat Values

20. 19 Sign Conventions If the temperature increases: Q and  T are positive Energy transfers into the system If the temperature decreases: Q and  T are negative Energy transfers out of the system

21. 20 Specific Heat of Water Water has the highest specific heat of most common materials Hydrogen and helium have higher specific heats This is responsible for many weather phenomena Moderate temperatures near large bodies of water Global wind systems Land and sea breezes

22. 21 Fig. 17-2, p. 535

23. 22 Calorimetry One technique for measuring specific heat involves heating a material, adding it to a sample of water, and recording the final temperature This technique is known as calorimetry A calorimeter is a device in which this energy transfer takes place

24. 23 Calorimetry, cont The system of the sample and the water is isolated The calorimeter allows no energy to enter or leave the system Conservation of energy requires that the amount of energy that leaves the sample equals the amount of energy that enters the water Conservation of Energy gives a mathematical expression of this: Q cold = - Q hot

25. 24 Calorimetry, final The negative sign in the equation is critical for consistency with the established sign convention Since each Q = m c  T, c unknown can be found Technically, the mass of the water’s container should be included, but if m w >>m container it can be neglected

26. 25 Phase Changes A phase change is when a substance changes from one form to another Two common phase changes are Solid to liquid (melting) Liquid to gas (boiling) During a phase change, there is no change in temperature of the substance

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29. 28 17.3 Latent Heat Different substances react differently to the energy added or removed during a phase change Due to their different molecular arrangements The amount of energy also depends on the mass of the sample If an amount of energy Q is required to change the phase of a sample of mass m,

30. 29 Latent Heat, cont The quantity L is called the latent heat of the material Latent means hidden The value of L depends on the substance as well as the actual phase change

31. 30 Latent Heat, final The latent heat of fusion, L f, is used during melting or freezing The latent heat of vaporization, L v, is used when the phase change boiling or condensing The positive sign is used when the energy is transferred into the system This will result in melting or boiling The negative sign is used when energy is transferred out of the system This will result in freezing or condensation

32. 31 Sample Latent Heat Values

33. 32 Graph of Ice to Steam Fig 17.3

34. 33 Warming Ice, Graph Part A Start with one gram of ice at –30.0º C During A, the temperature of the ice changes from –30.0º C to 0º C Use Q = m c ice ΔT In this case, 62.7 J of energy are added

35. 34 Melting Ice, Graph Part B Once at 0º C, the phase change (melting) starts The temperature stays the same although energy is still being added Use Q = m L f The energy required is 333 J On the graph, the values move from 62.7 J to 396 J

36. 35 Warming Water, Graph Part C Between 0º C and 100º C, the material is liquid and no phase changes take place Energy added increases the temperature Use Q = m c water ΔT 419 J are added The total is now 815 J

37. 36 Boiling Water, Graph Part D At 100º C, a phase change occurs (boiling) Temperature does not change Use Q = m L v This requires2260 J The total is now 3070 J

38. 37 Heating Steam After all the water is converted to steam, the steam will heat up No phase change occurs The added energy goes to increasing the temperature Use Q = m c steam ΔT In this case, 40.2 J are needed The temperature is going to 120 o C The total is now 3110 J

39. 38 State Variables State variables describe the state of a system In the macroscopic approach to thermodynamics, variables are used to describe the state of the system Pressure, temperature, volume, internal energy These are examples of state variables The macroscopic state of an isolated system can be specified only if the system is in internal thermal equilibrium

40. 39 Transfer Variables Transfer variables have values only when a process occurs in which energy is transferred across the boundary of a system Transfer variables are not associated with any given state of the system, only with changes in the state Heat and work are transfer variables Example of heat: we can only assign a value of the heat if energy crosses the boundary by heat

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43. 42 17.4 Work in Thermodynamics Work can be done on a deformable system, such as a gas Consider a cylinder with a moveable piston A force is applied to slowly compress the gas The compression is slow enough for all the system to remain essentially in thermal equilibrium This is said to occur in a quasi- static process A simplification model Fig 17.4

44. 43 Work, 2 The piston is pushed downward by a force through a displacement: A. dy is the change in volume of the gas, dV Therefore, the work done on the gas is dW = -P dV

45. 44 Work, 3 Interpreting dW = - P dV If the gas is compressed, dV is negative and the work done on the gas is positive If the gas expands, dV is positive and the work done on the gas is negative If the volume remains constant, the work done is zero The total work done is

46. 45 PV Diagrams Used when the pressure and volume are known at each step of the process The state of the gas at each step can be plotted on a graph called a PV diagram This allows us to visualize the process through which the gas is progressing The curve is called the path Fig 17.5

47. 46 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 17.5

48. 47 PV Diagrams, cont The work done on a gas in a quasi- static process that takes the gas from an initial state to a final state is the negative of the area under the curve on the PV diagram, evaluated between the initial and final states This is true whether or not the pressure stays constant The work done does depend on the path taken

49. 48 Work Done By Various Paths Each of these processes have the same initial and final states The work done differs in each process The work done depends on the path

50. 49 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 17.6

51. 50 Work From A PV Diagram, Example 1 The volume of the gas is first reduced from V i to V f at constant pressure P i Next, the pressure increases from P i to P f by heating at constant volume V f W = -P i (V f – V i )

52. 51 Work From A PV Diagram, Example 2 The pressure of the gas is increased from P i to P f at a constant volume The volume is decreased from V i to V f W = -P f (V f – V i )

53. 52 Work From A PV Diagram, Example 3 The pressure and the volume continually change The work is some intermediate value between –P f (V f – V i ) and –P i (V f – V i ) To evaluate the actual amount of work, the function P(V) must be known

54. 53 Heat Transfer, Example 1 The energy transfer, Q, into or out of a system also depends on the process The energy reservoir is a source of energy that is considered to be so great that a finite transfer of energy does not change its temperature The piston is pushed upward, the gas is doing work on the piston Fig 17.7

55. 54 Heat Transfer, Example 2 This gas has the same initial volume, temperature and pressure as the previous example The final states are also identical No energy is transferred by heat through the insulating wall No work is done by the gas expanding into the vacuum Fig 17.7

56. 55 Energy Transfer, Summary Energy transfers by heat, like the work done, depend on the initial, final, and intermediate states of the system Both work and heat depend on the path taken Both depend on the process followed between the initial and final states of the system

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60. 59 17.5 The First Law of Thermodynamics The First Law of Thermodynamics is a special case of the Law of Conservation of Energy It takes into account changes in internal energy and energy transfers by heat and work The First Law of Thermodynamics states that  E int = Q + W A special case of the continuity equation All quantities must have the same units of measure of energy

61. 60 The First Law of Thermodynamics, cont For infinitesimal changes in a system dE int = dQ + dW No practical distinction exists between the results of heat and work on a microscopic scale Each can produce a change in the internal energy of the system Once a process or path is defined, Q and W can be calculated or measured

62. 61 17.6 Adiabatic Process An adiabatic process is one during which no energy enters or leaves the system by heat Q = 0 This is achieved by Thermally insulating the walls of the system Having the process proceed so quickly that no heat can be exchanged Fig 17.8

63. 62 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 17.8

64. 63 Adiabatic Process, cont Since Q = 0,  E int = W If the gas is compressed adiabatically, W is positive so  E int is positive and the temperature of the gas increases Work is done on the gas If the gas is expands adiabatically the temperature of the gas decreases

65. 64 Adiabatic Processes, Examples Some important examples of adiabatic processes related to engineering are The expansion of hot gases in an internal combustion engine The liquefaction of gases in a cooling system The compression stroke in a diesel engine

66. 65 Adiabatic Free Expansion This is an example of adiabatic free expansion The process is adiabatic because it takes place in an insulated container Because the gas expands into a vacuum, it does not apply a force on a piston and W = 0 Since Q = 0 and W = 0,  E int = 0 and the initial and final states are the same No change in temperature is expected Fig 17.7

67. 66 Isobaric Process An isobaric process is one that occurs at a constant pressure The values of the heat and the work are generally both nonzero The work done is W = P (V f – V i ) where P is the constant pressure

68. 67 Isovolumic Process An isovolumic process is one in which there is no change in the volume Since the volume does not change, W = 0 From the First Law,  E int = Q If energy is added by heat to a system kept at constant volume, all of the transferred energy remains in the system as an increase in its internal energy

69. 68 Isothermal Process An isothermal process is one that occurs at a constant temperature Since there is no change in temperature,  E int = 0 Therefore, Q = - W Any energy that enters the system by heat must leave the system by work

70. 69 Isothermal Process, cont This is a PV diagram of an isothermal expansion The curve is a hyperbola The curve is called an isotherm Fig 17.9

71. 70 Isothermal Expansion, Details The curve of the PV diagram indicates PV = constant The equation of a hyperbola The work done on the ideal gas can be calculated by

72. 71 Special Processes, Summary Adiabatic No heat exchanged Q = 0 and  E int = W Isobaric Constant pressure W = P (V f – V i ) and  E int = Q + W Isothermal Constant temperature  E int = 0 and Q = - W

73. 72 Cyclic Processes A cyclic process is one that originates and ends at the same state This process would not be isolated On a PV diagram, a cyclic process appears as a closed curve The internal energy must be zero since it is a state variable If  E int = 0, Q = -W In a cyclic process, the net work done on the system per cycle equals the area enclosed by the path representing the process on a PV diagram

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75. 74 Fig. 17-11, p. 546

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83. 82 17.7 Molar Specific Heat Several processes can change the temperature of an ideal gas Since  T is the same for each process,  E int is also the same The heat is different for the different paths The heat associated with a particular change in temperature is not unique Fig 17.11

84. 83 Molar Specific Heat, 2 We define specific heats for two processes that frequently occur Changes with constant pressure Changes with constant volume Using the number of moles, n, we can define molar specific heats for these processes

85. 84 Molar Specific Heat, 3 Molar specific heats: Q = n C v  T for constant volume processes Q = n C p  T for constant pressure processes Q (in a constant pressure process) must account for both the increase in internal energy and the transfer of energy out of the system by work Q (constant P) > Q (constant V) for given values of n and  T

86. 85 Ideal Monatomic Gas A monatomic gas contains one atom per molecule When energy is added to a monatomic gas in a container with a fixed volume, all of the energy goes into increasing the translational kinetic energy of gas There is no other way to store energy in such a gas

87. 86 Ideal Monatomic Gas, cont Therefore, E int = 3/2 n R T E is a function of T only In general, the internal energy of an ideal gas is a function of T only The exact relationship depends on the type of gas At constant volume, Q =  E int = n C v  T This applies to all ideal gases, not just monatomic ones

88. 87 Monatomic Gases, final Solving for C v gives C v = 3/2 R = 12.5 J/mol. K For all monatomic gases This is in good agreement with experimental results for monatomic gases In a constant pressure process,  E int = Q + W and C p – C v = R This also applies to any ideal gas C o = 5/2 R = 20.8 J/mol. K

89. 88 Ratio of Molar Specific Heats We can also define Theoretical values of C V, C P, and  are in excellent agreement for monatomic gases

90. 89 Fig. 17-13, p. 548

91. 90 If you can't see the image above, please install Shockwave Flash Player.Shockwave Flash Player. If this active figure can’t auto-play, please click right button, then click play. NEXT Active Figure 17.13

92. 91 Sample Values of Molar Specific Heats

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96. 95 17.8 Adiabatic Process for an Ideal Gas At any time during the process, PV = nRT is valid None of the variables alone are constant Combinations of the variables may be constant The pressure and volume of an ideal gas at any time during an adiabatic process are related by PV  = constant All three variables in the ideal gas law (P, V, T) can change during an adiabatic process

97. 96 Fig. 17-14, p. 551

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100. 99 17.9 Equipartition of Energy With complex molecules, other contributions to internal energy must be taken into account One possible energy is the translational motion of the center of mass Fig 17.15

101. 100 Equipartition of Energy, 2 Rotational motion about the various axes also contributes We can neglect the rotation around the y axis since it is negligible compared to the x and z axes Fig 17.15

102. 101 Equipartition of Energy, 3 The translational motion adds three degrees of freedom The rotational motion adds two degrees of freedom Therefore, E int = 5/2 n R T and C V = 5/2 R = 20.8 J/mol. K The model predicts that  = 7/5 = 1.40

103. 102 Equipartition of Energy, 4 The molecule can also vibrate There is kinetic energy and potential energy associated with the vibrations This adds two more degrees of freedom Fig 17.15

104. 103 Equipartition of Energy, 5 Considering all the degrees of freedom: E int = 7/2 n R T C v = 7/2 R = 29.1 J / mol. K  = 1.29 This doesn’t agree well with experimental results A wide range of temperature needs to be included

105. 104 Agreement with Experiment Molar specific heat is a function of temperature At low temperatures, a diatomic gas acts like a monatomic gas C V = 3/2 R Fig 17.16

106. 105 Agreement with Experiment, cont At about room temperature, the value increases to C V = 5/2 R This is consistent with adding rotational energy but not vibrational energy At high temperatures, the value increases to C V = 7/2 R This includes vibrational energy as well as rotational and translational

107. 106 Complex Molecules For molecules with more than two atoms, the vibrations are more complex The number of degrees of freedom is larger The more degrees of freedom available to a molecule, the more “ways” there are to store energy This results in a higher molar specific heat

108. 107 Quantization of Energy To explain the results of the various molar specific heats, we must use some quantum mechanics Classical mechanics is not sufficient The rotational and vibrational energies of a molecule are quantized

109. 108 Quantization of Energy, 2 The energy level diagram shows the rotational and vibrational states of a diatomic molecule Fig 17.17

110. 109 Quantization of Energy, 3 The vibrational states are separated by larger energy gaps than are rotational states At low temperatures, the energy gained during collisions is generally not enough to raise it to the first excited state of either rotation or vibration

111. 110 Quantization of Energy, 4 Even though rotation and vibration are classically allowed, they do not occur As the temperature increases, the energy of the molecules increases In some collisions, the molecules have enough energy to excite to the first excited state As the temperature continues to increase, more molecules are in excited states

112. 111 Quantization of Energy, final At about room temperature, rotational energy is contributing fully At about 1000 K, vibrational energy levels are reached At about 10000 K, vibration is contributing fully to the internal energy

113. 112 p. 554

114. 113 17.10 Mechanisms of Heat Transfer We want to know the rate at which energy is transferred There are various mechanisms responsible for the transfer Mechanisms include Conduction Convection Radiation

115. 114 Conduction The transfer can be viewed on an atomic scale It is an exchange of kinetic energy between microscopic particles by collisions The microscopic particles can be atoms, molecules or free electrons Less energetic particles gain energy during collisions with more energetic particles Rate of conduction depends upon the characteristics of the substance

116. 115 Conduction, cont. In general, metals are good conductors They contain large numbers of electrons that are relatively free to move through the metal They can transport energy from one region to another Poor conductors include asbestos, paper, gases Conduction can occur only if there is a difference in temperature between two parts of the conducting medium

117. 116 Conduction, equation The slab allows energy to transfer from the region of higher temperature to the region of lower temperature The rate of transfer is given by Fig 17.18

118. 117 Conduction, equation explanation A is the cross-sectional area Δx is the thickness of the slab Or the length of a rod Power is in Watts when Q is in Joules and t is in seconds k is the thermal conductivity of the material Good conductors have high k values and good insulators have low k values

119. 118 Temperature Gradient The quantity |dT / dx| is called the temperature gradient of the material It measures the rate at which temperature varies with position For a rod, the temperature gradient can be expressed as Fig 17.19

120. 119 Rate of Energy Transfer in a Rod Using the temperature gradient for the rod, the rate of energy transfer becomes

121. 120 Some Thermal Conductivities

122. 121 Some More Thermal Conductivities

123. 122 More Thermal Conductivities

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128. 127 Convection Energy transferred by the movement of a fluid When the movement results from differences in density, it is called natural convection When the movement is forced by a fan or a pump, it is called forced convection

129. 128 Fig. 17-21, p. 557

130. 129 Convection example Air directly above the radiator is warmed and expands The density of the air decreases, and it rises A continuous air current is established Fig 17.22

131. 130 Radiation Radiation does not require physical contact All objects radiate energy continuously in the form of electromagnetic waves due to thermal vibrations of the molecules Rate of radiation is given by Stefan’s Law

132. 131 Stefan’s Law P = σ A e T 4 P is the rate of energy transfer, in Watts σ = 5.6696 x 10 -8 W/m 2 K 4 Stefan-Boltzmann constant A is the surface area of the object e is a constant called the emissivity e varies from 0 to 1 The emissivity is also equal to the absorptivity T is the temperature in Kelvins

133. 132 Energy Absorption and Emission by Radiation With its surroundings, the rate at which the object at temperature T with surroundings at T o radiates is P net = σ A e (T 4 –T o 4 ) When an object is in equilibrium with its surroundings, it radiates and absorbs at the same rate Its temperature will not change

134. 133 17.11 Earth’s Energy Balance Energy arrives at the Earth by electro- magnetic radiation from the Sun This energy is absorbed at the surface of the Earth and reradiated out into space This follows Stefan’s Law Assume any change in the temperature of the Earth over a time interval is (approximately) zero

135. 134 Earth’s Energy Balance, 2 Energy from the Sun arrives from one direction Energy is emitted by the Earth in all directions From energy balance analysis, the temperature of the Earth should be about 255 K The actual temperature is about 288 K, due to atmospheric affects Fig 17.23