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Antiderivatives and Indefinite Integration Lesson 5.1.

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Presentation on theme: "Antiderivatives and Indefinite Integration Lesson 5.1."— Presentation transcript:

1 Antiderivatives and Indefinite Integration Lesson 5.1

2 Reversing Differentiation An antiderivative of function f is  a function F  which satisfies F’ = f Consider the following: We note that two antiderivatives of the same function differ by a constant

3 Reversing Differentiation General antiderivatives f(x) = 6x 2 F(x) = 2x 3 + C  because F’(x) = 6x 2 k(x) = sec 2 (x) K(x) = tan(x) + C  because K’(x) = k(x)

4 Differential Equation A differential equation in x and y involves  x, y, and derivatives of y Examples Solution – find a function whose derivative is the differential given

5 Differential Equation When Then one such function is The general solution is

6 Notation for Antiderivatives We are starting with Change to differential form Then the notation for antiderivatives is "The antiderivative of f with respect to x"

7 Basic Integration Rules Note the inverse nature of integration and differentiation Note basic rules, pg 286

8 Practice Try these

9 Finding a Particular Solution Given Find the specific equation from the family of antiderivatives, which contains the point (3,2) Hint: find the general antiderivative, use the given point to find the value for C

10 Assignment A Lesson 5.1 A Page 291 Exercises 1 – 55 odd

11 Slope Fields Slope of a function f(x)  at a point a  given by f ‘(a) Suppose we know f ‘(x)  substitute different values for a  draw short slope lines for successive values of y Example

12 Slope Fields For a large portion of the graph, when We can trace the line for a specific F(x)  specifically when the C = -3

13 Finding an Antiderivative Using a Slope Field Given We can trace the version of the original F(x) which goes through the origin.

14 Vertical Motion Consider the fact that the acceleration due to gravity a(t) = -32 fps Then v(t) = -32t + v 0 Also s(t) = -16t 2 + v 0 t + s 0 A balloon, rising vertically with velocity = 8 releases a sandbag at the instant it is 64 feet above the ground  How long until the sandbag hits the ground  What is its velocity when this happens? Why?

15 Rectilinear Motion A particle, initially at rest, moves along the x- axis at velocity of At time t = 0, its position is x = 3  Find the velocity and position functions for the particle  Find all values of t for which the particle is at rest

16 Assignment B Lesson 5.1 B Page 292 Exercises 77 – 93, EOO


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