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Chapter 8 Percentage Composition
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Water is made of hydrogen and oxygen. How many grams of each are in the sample of water below?
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Percent Composition Mass of element Formula Mass of compound X 100 X 100 % = Percent composition is the percent by mass of an element within a compound. Divide the mass of each element by the formula mass of the compound
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Percent Composition of H 2 O 2 X H = 2 X 1.0 g = 2.0 g 1 X O = 1 X 16.0 g = 16.0 g gram formula mass = 2.0 g + 16.0 g = 18.0 g % H = 2.0g X 100 = 11.2% 18.0g % O = 16.0g X 100 = 88.8% 18.0g
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Percent Composition of H 2 O 2 X H = 2 X 1.0 g = 2.0 g 1 X O = 1 X 16.0 g = 16.0 g gram formula mass = 2.0 g + 16.0 g = 18.0 g % H = 2.0g X 100 = 11.2% 18.0g % O = 16.0g X 100 = 88.8% 18.0g What does this mean?
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Pure water’s mass is 11.2% hydrogen and 88.8% oxygen. (0.112)(128.98g) = 14.45g H (.888)(128.98g) = 114.53g O or 128.98g – 14.45g = 114.53g O 11.2% H 88.8% O
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Percentage Composition Remember that you have to calculate the formula mass!
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Determine the Percent Composition of C 6 H 12 O 6
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6 X C = 6 X 12.0 g = 72.0g 12 X H = 12 X 1.0g = 12.0g 6 X O = 6 X 16.0g = 96.0g gfm = 180.0 grams/mole
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Determine the Percent Composition of C 6 H 12 O 6 6 X C = 6 X 12.0 g = 72.0g 12 X H = 12 X 1.0g = 12.0g 6 X O = 6 X 16.0g = 96.0g gfm = 180.0 grams/mole % C = % H = % O = (72.0g/180.0g) X 100 = 40.0% (12.0g/180.0g) X 100 = 6.67% (96.0g/180.0g) X 100 = 53.3%
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How many grams of carbon are in 156g C 6 H 12 O 6 6 (156g)(0.400) = 62.4g carbon 12 6 Molar % C = % H = % O = (72.0g/180.0g) X 100 = 40.0% (12.0g/180.0g) X 100 = 6.67% (96.0g/180.0g) X 100 = 53.3%
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What is this? a
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Iron Pyrite “Fool’s Gold” (FeS 2 ) a
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How many grams of sulfur are in this 28.8g sample of iron pyrite FeS 2 ? a
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a 15.4g S
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How many grams of sulfur are in this 28.8g sample of iron pyrite FeS 2 ? a 15.4g S Fe + 2(S) 55.8 + 2( 32.1) = 120.0 g/mol %S = 64.2/120.0 x 100= 53.5%S 28.8g x 0.535 = 15.4g S
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Homework Molarity Worksheet (Due Tomorrow). Percentage Composition Worksheet (Due in 2 Days).
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