Download presentation
Presentation is loading. Please wait.
Published byDinah Williams Modified over 8 years ago
1
1 Temporal logic
2
2 Prop. logic: model and reason about static situations. Example: Are there truth values that can be assigned to x,y simultaneously that satisfy x Ç : y ? To reason about programs, we need dynamics!
3
3 Need dynamics In prop. logic: State = a full assignment Formula = a set of states i.e., the set of assignments that satisfy it. What we need is a sequence of states. possibly an infinite sequence for reactive systems. Each such sequence is called a behavior, or a computation.
4
4 Need dynamics The checked system: M. Specification of the possible behaviors of M: We will ask whether the following holds: M ² i.e., do all behaviors of M satisfy the property .
5
5 History of Temporal Logic Designed by philosophers to study the way that time is used in natural language arguments Brought to Computer Science by Amir Pnueli in 1977. Has proved to be useful for specification of reactive systems
6
6 Linear Temporal Logic (LTL) In LTL time is implicit, discrete, has an initial moment with no predecessors, and infinite in the future The model of LTL formula is infinite sequence of states s 0, s 1, s 2, …
7
7 LTL: Syntax := ( ) | ¬ | Æ Ç U R G F |X | p Elements : Atomic propositions Boolean operators ¬ Temporal operators G F X U R
8
8 LTL: Syntax := ( ) | ¬ | Æ Ç U R G F |X | p G Always ( = “Henceforth ”) F Eventually (= “ in the future”) X “next-time ” U “ until ” R “ Release ”
9
9 Semantic Intuition G f - always f F f – eventually f X f – next state f U r – until f R r – releases f f f f f f f f f f f f r r r,f r r f r r r r r r
10
10 Semantic Semantic is given with respect to paths = s 0 s 1 s 2 … Suffix of trace starting at s i i = s i s i+1 s i+2 … A system satisfies an LTL formula if each path through the system satisfies .
11
11 Semantic (cont ’ d) k ² a iff a s k k ² iff not k ² k ² iff k ² and k ² k ² iff k ² or k ² k ² X iff k 1 ² k ² F iff exists i k i ² k ² G iff for all i k i ² k ² U iff exists i k i ² and for all k j < i. j ² k ² R iff for all j k, if for every k · i < j not i ² then j ²
12
12 LTL Identities Write G with F:G = F Write F with U: F = ( true U ) Write R with U: R = ( U ) Every LTL formula can be rewritten using only operators X U
13
13 Combinations GF p “ p will happen infinitely often ” FG p “ p will happen from some point forever ”. (GF p) ! (GF q) “ If p happens infinitely often, then q also happens infinitely often ”. (Now: Examples of specifying with LTL )
14
14 Limitations of LTL Is there a temporal behavior that we cannot express with LTL ? Property: “ p holds in every even state ” Unexpressible in LTL. There are extensions to LTL that solve these type of problems. We will not learn them.
15
15 Two classes of properties Safety properties: nothing ‘ bad ’ will happen. A counterexample is a finite loop-free sequence of states. Example: G(p → X q) pp,q Bad state Initial state
16
16 Two classes of properties Liveness properties: something ‘ good ’ will happen. A counterexample is an infinite trace, showing that this good thing NEVER happens. In a finite state model, this is represented as a finite sequence of states ending with a loop. Example: F p :p:p :p:p :p:p :p:p :p:p :p:p Initial state
17
17 A Spring Example s1s3s2 pull release S2 S3 0 = s1 s2 s1 s2 s1 s2 s1 … 1 = s1 s2 s3 s3 s3 s3 s3 … 2 = s1 s2 s1 s2 s3 s3 s3 … …
18
18 LTL satisfaction by a single sequence s1s3s2 pull release 2 = s1 s2 s1 s2 s3 s3 s3 … 2 ² S2 ?? 2 ² X S2 ?? 2 ² XX S2 ?? 2 ² F S2 ?? 2 ² G S2 ?? 2 ² FG S2 ?? 2 ² FG S3 ?? 2 ² ¬ FG S2 ?? 2 ² (¬S2) U S3 ?? 2 ² G (¬S2 ! X S2) ??
19
19 LTL satisfaction by a system s1s3s2 pull release A ² S2 ?? A ² X S2 ?? A ² XX S2 ?? A ² F S2 ?? A ² G S2 ?? A ² FG S2 ?? A ² FG S3 ?? A ² ¬FG S2 ?? A ² (¬S2) U S3 ?? A ² G(¬S2 ! X S2) ?? A:
20
20 The problem of vacuity Consider the following property : G(request F ack)... and a system M that never sends requests. The property is satisfied: M ² Is it ok ? This can indicate a bug in M or in the property.
21
21 The problem of vacuity Consider the following property : G(p U (p Ç q))... and a system M which satisfies Gq. The property is satisfied: M ² Is this what the user intended ? A bug in the property? Equivalent to G (p Ç q) Otherwise change the property.
22
22 The problem of vacuity When a formula passes not due to the ‘ right ’ reasons we might be fooling ourselves that everything is ok. Is there a way to check for such errors ?
23
23 The problem of vacuity Let be an LTL formula in negation normal form. is said to be vacuous in M if there exists an occurrence of an atom a 2 AP( ) such that M ² [ a à false] (or M ² [ a à true] if a appears negatively). We check vacuity only after we know that M ²
24
24 The problem of vacuity Example 1: : G(request F ack) Check : G(true F ack) Suppose that M ² Either: This contradicts the user ’ s understanding of M. There is a bug in M. This was the intention. So change to the stronger formula GF ack.
25
25 The problem of vacuity Example 1: : G(request F ack) Check : G(request F false) Suppose that M ² Either: This contradicts the user ’ s understanding of M. There is a bug in M. This was the intention. So change to the stronger formula G : request.
26
26 The problem of vacuity Example 2: : G(p U (p Ç q)) Check : G(false U (p Ç q)) For all M, if M ² then M ² . Hopefully the user will realize that it should be G(p Ç q).
27
27 The problem of vacuity Example 2: : G(p U (p Ç q)) Check : G(p U (false Ç q)) If M ² then there is no path satisfying G(p Æ : q) Error in the model ? Should we change the property to ?
28
28 The problem of vacuity Example 2: : G(p U (p Ç q)) Check : G(p U (p Ç false)) If M ² then M ² Gp Error in the model ? Should we change the property to ?
29
29 Mutual vacuity Consider = G(a Ç b Ç c).. and M: M ² G(b Ç c)// nothing else to remove M ² G(a Ç b)// can still remove b M ² G(a) Conclusion: order of vacuity-checks matters! ab ac
30
30 Mutual vacuity The mutual vacuity problem: what is the largest number of literal ocurrences that can be replaced with false simultanuously without falsifying M in ? Formally: find largest S µ lit-occur( ) such that M ² [a à false | a 2 S]
31
31 Vacuity checks in the industry Most commercial model-checkers check for vacuity automatically Typically only a few ‘ important checks ’, not all possible. Too expansive in practice to check for mutual vacuity.
32
32 Representing Concurrent Systems The ‘ spring ’ system is an example of a ‘ Kripke structure ’ Kripke structure: a tuple M = (S, S 0, R, L), where S – set of all states of the system S 0 – set of initial states R – transition relation between states L – a function that associates each state with set of propositions true in that state
33
33 Kripke Model Set of states S {q 1,q 2,q 3 } Set of initial states S 0 {q 1 } Set of atomic propositions AP {a,b} a a,bb q1q1 q3q3 q2q2
34
34 What ’ s next ? A Kripke structure is a special variant of an automaton. Next, we will learn about automata.
Similar presentations
© 2024 SlidePlayer.com. Inc.
All rights reserved.