1. Project Crashing

2. c=6 e=9 b=6 a=7 f=8 g=5 d=4 Given the information below, what is the total additional cost to crash the project as much as possible? Activity Normal Duration Crashed Duration Normal Cost Crashed Cost Additional Cost/day a764050 b65 65 c645066 d424050 e9970 f8560105 g544552 Project Duration Crash Activity Additional Cost New Critical Path 21-- acf Path Durations a c f = 21 a d g = 16 b e g = 20 if then cost result

3. a d g h e f c b PERT Example Activity Immediate Predecessor Optimistic Duration Most Likely Pessimistic Duration Expected Duration t e V t Variance a--151820 b--20 22 c--121416 da777 eb81112 fc172124 gb,d101215 he,f91011 Critical path: Expected project duration T = Standard deviation of critical path σ cp = Prob(X > 48)? Prob(X < 43)? Prob(43 < X < 48)? Predict a completion date that you’re 80% sure you can meet.