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1 Math 4030 – 10b Inferences Concerning Proportions
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2 Population proportion p is: p(100)% of the subjects in the population has the property of our interest; if randomly select one subject from the population, the probability is p that the subject has the property of our interest; if we take a sample of size n, of which X subjects have the property of our interest, then the sample proportion is Sample Proportion:
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3 Distribution of sample proportion X/n: For n ≥ 30 Confidence Interval for p (Sec. 10.1): Maximum error of estimate for p
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4 Sample size calculation: p?? Use p from similar population; Use ¼ as maximum of p(1-p); If = 0.05, we may use n = 1/E 2
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5 For Hypothesis Testing (Sec. 10.2)
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6 A new method is under development for making disks of a superconducting material. 50 disks are made by each method (new and old) and they are checked for superconductivity when cooled with liquid nitrogen. Compare 2 proportions: Old Method 1New Method 2Total Superconductors314273 Failures19827 Total50 100 Need to claim that the new method makes improvement.
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7 or Sample proportions: Distribution under the assumption Distribution of Sample Proportion Difference:
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8 Hypothesis Testing: Null hypothesis Alternative hypothesis Level of significance: Critical value and Critical region: for large sample, we use the z-test Sample statistic calculation: Conclusion: Reject the null hypothesis, …
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9 Confidence interval for the difference: More than Up to
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10 Compare Several Proportions (Sec. 10.3): Sample 1Sample 2…Sample kTotal Successesx1x1 x2x2 …xkxk x Failuresn 1 -x 1 n 2 -x 2 …n k -x k n - x Totaln1n1 n2n2 …nknk n From k independent samples from k populations, we have
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11 for each j, and large sample. Sampling distribution if are k population proportions: Combined has chi-square distribution with df = k – 1. Normal approximate binomial.
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12 Observed frequency Expected frequency
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13 Hypothesis Testing: Null hypothesis Alternative hypothesis Sample statistic: where (Pooled proportion) (Expected Cell Frequency) (Observed Cell Frequency) with df = k – 1,
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14 Example. Four methods are under development for making disks of a superconducting material. 40, 50, 60, 70 disks are made by each of 4 methods, respectively, and they are checked for superconductivity when cooled with liquid nitrogen. Method 1 Method 2 Method 3 Method 4 Total Supercond uctors 2132 45130 Failures98282570 Total30406070200
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15 First we need to know whether 4 methods have any difference. Null hypothesis: Alternative hypothesis: are not all equal. Level of significance: = 0.05 Critical region: With df = 4 – 1 = 3, we have Critical region is: (7.815, ). Statistic from sample: We need to calculate the expected frequencies.
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16 Method 1Method 2Method 3Method 4Total Supercon ductors 21 (19.5) 32 (26) 32 (39) 45 (45.5) 130 Failures 9 (10.5) 8 (14) 28 (21) 25 (24.5) 70 Total30406070200 2 = 7.891 Expected frequencies: Conclusion: Since the sample statistic falls in the critical region, we reject the null hypothesis. Four methods are not all the same.
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How do these methods differ? 17 Gives confidence interval for each of the 4 population (method) proportion. Use Excel, we find
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18 Method 1 Method 2 Method 3 Method 4 0.4 0.90.8 0.70.6 0.5 p
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