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Basic Stoichiometry Problems
Please use these examples to solve today’s problems
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Example #1 If 35.80g of aluminum chloride reacts with excess silver nitrate, how many grams of the ppt will be formed? 1AlCl3(aq) + 3AgNO3(aq) Al(NO3)3(aq) + 3AgCl(s) 35.80g AlCl mol AlCl mol AgCl g AgCl 132.76g AlCl mol AlCl mol AgCl = 115.9g AgCl
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Example #2 15.0ml of a 3.0M magnesium chloride solution reacts with excess silver nitrate, how many grams of ppt will be formed? 1 MgCl2(aq) + 2 AgNO3(aq) Mg(NO3)2(aq) + 2AgCl(s) 15.0ml 1 Liter mole MgCl mol AgCl g AgCl 1000l liter mol MgCl mol AgCl = 12.9g AgCl
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Example #3 12.01g of ammonium carbonate reacts with excess ferrous bromide. How many grams of the ppt will be formed? 1(NH4)2CO3(aq) + FeBr2(aq) 2NH4Br(aq) + 1FeCO3 (s) 12.01g(NH4)2CO3 1mol (NH4)2CO3 1mol FeCO g 96.11g mol (NH4)2CO mol FeCO3 = 14.48g FeCO3
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